3月10号周二课堂练习：四则运算二

// asdfg.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include "stdlib.h"
#include<stdio.h>
#include <time.h>
#include <windows.h>
int fx1(int a0)
{      
	printf("请输入要打印的题目数：");
	scanf("%d", &a0);
	while (a0 <= 0)  //题数为正数
	{
		printf("请重新输入题目数：");
		scanf("%d", &a0);
	};
	return 0;
	}

int fx2(int a2)
{
	     
	printf("请输入运算数的范围：");
	scanf("%d", &a2);
	while (a2 <= 0)  //运算数为正数
	{
		printf("请重新输入范围：");
		scanf("%d", &a2);
	};
	return 0;
}


int fx3(int a1)
{

//题目中是否有乘除法
	printf("请选择乘除法（是1；否0）：");
	scanf("%d", &a1);
	while ((a1 != 1)&(a1 != 0)) //只能选择1或0
	{
		printf("请重新输入数值：");
		scanf("%d", &a1);
	};
	return 0;
}  

int fx4(int a3)
{
	
//题目结果是否有负数
	printf("请选择有无负数（是1；否0）：");
	scanf("%d", &a3);
	while ((a3 != 1)&(a3 != 0))  //只能选择1或0
	{
		printf("请重新输入数值：");
		scanf("%d", &a3);
	};
	return 0;

}
int fx5(int a4)

{

	//结果是否有余数
	printf("请选择有无余数（是1；否0）：");
	scanf("%d", &a4);
	while ((a4 != 1)&(a4 != 0))  //只能选择1或0
	{
		printf("请重新输入数值：");
		scanf("%d", &a4);
	};
	return 0;

} 
int fx6(int a5)
{


	//是否支持小数
	printf("请选择有无小数（是1；否0）：");
	scanf("%d", &a5);
	while ((a5 != 1)&(a5 != 0))  //只能选择1或0
	{
		printf("请重新输入数值：");
		scanf("%d", &a5);
	};
	return 0;
}
int fx7(int a6)
{

	//是否加括号
	printf("请选择有无括号（是1；否0）：");
	scanf("%d", &a6);
	while ((a6 != 1)&(a6 != 0))  //只能选择1或0
	{
		printf("请重新输入数值：");
		scanf("%d", &a6);
	};
	return 0;
}
int main()
{
	srand(time(NULL)); //避免题目重复
	int rand1, rand2, flag, i, j;
	int rand3, rand4;
	int a0, a1, a2, a3, a4 , a5 ,a6;
	printf("请按照提示进行输入\n");
	fx1(a0);
	fx2(a2);
	fx3(a1);
	fx4(a3);
	fx5(a4);
	fx6(a5);
	fx7(a6);
	    
	 //循环打印符合要求的题目
	 for (i = 0; i < a0; i++)
	 {
		 switch (a1)
		 {
			 case 1:j = rand() % 4; break;  //有乘除法
			 case 0:j = rand() % 2; break;  //无乘除法
		 }
		 rand1 = rand() % a2 + 1;
		 rand2 = rand() % a2 + 1;

			 //循环打印
			 if (j == 0)
			 {
			     switch (a6)
				     {
						 case 0:
								 switch (a5)
									 {
									 case 0:printf("%d+%d=\t\t", rand1, rand2); break;
									 case 1:
											 rand3 = rand() % 9 + 1;
											 rand4 = rand() % 9 + 1;
											 printf("%d.%d+%d.%d=\t\t", rand1, rand3, rand2, rand4); break;
										 }
								 break;
				
						 case 1:
							     switch (a5)
								     {
								     case 0:printf("（%d+%d）=\t", rand1, rand2); break;
								     case 1:
									         rand3 = rand() % 9 + 1;
									         rand4 = rand() % 9 + 1;
									         printf("（%d.%d+%d.%d）=\t", rand1, rand3, rand2, rand4); break;
									     }
							     break;
					}
			 }
		 if (j == 1)
			 {
			     switch (a3)
				     {
						 case 1:                   //结果可有负数
								 break;
						 case 0:                   //结果无负数
								 if (rand1 < rand2)            //被减数比减数小则交换
									 {
										 flag = rand1;
										 rand1 = rand2;
										 rand2 = flag;
									 }
								 break;
					 }
			     switch (a6)
				     {
						 case 0:
								 switch (a5)
									 {
									 case 0:printf("%d-%d=\t\t", rand1, rand2); break;
									 case 1:
											 rand3 = rand() % 9 + 1;
											 rand4 = rand() % 9 + 1;
											 printf("%d.%d-%d.%d=\t\t", rand1, rand3, rand2, rand4); break;
										 }
								 break;
			
						 case 1:
							     switch (a5)
								     {
								     case 0:printf("（%d-%d）=\t", rand1, rand2); break;
								     case 1:
									         rand3 = rand() % 9 + 1;
									         rand4 = rand() % 9 + 1;
									         printf("（%d.%d-%d.%d）=\t", rand1, rand3, rand2, rand4); break;
									     }
							     break;
						}
			 }
		 if (j == 2)
		 {
			     switch (a6)
			     {
					 case 0:
							 switch (a5)
								 {
								 case 0:printf("%d*%d=\t\t", rand1, rand2); break;
								 case 1:
										 rand3 = rand() % 9 + 1;
										 rand4 = rand() % 9 + 1;
										 printf("%d.%d*%d.%d=\t\t", rand1, rand3, rand2, rand4); break;
									 }
							 break;
		
					 case 1:
						     switch (a5)
							     {
							     case 0:printf("（%d*%d）=\t", rand1, rand2); break;
							     case 1:
								         rand3 = rand() % 9 + 1;
								         rand4 = rand() % 9 + 1;
								         printf("（%d.%d*%d.%d）=\t", rand1, rand3, rand2, rand4); break;
								     }
						     break;
						 }
		 }
		 if (j == 3)
			 {
				 switch (a4)
					 {
					 case 1:                         //结果可有余数
						 break;
					 case 0:                        //结果无余数
						 while (rand1%rand2 != 0)            //如果不能整除，则重新生成
							 {
								 rand1 = rand() % a2 + 1;
								 rand2 = rand() % a2 + 1;
							 };
						 break;
							 }
				 switch (a6)
					 {
					 case 0:
							 switch (a5)
								 {
								 case 0:printf("%d/%d=\t\t", rand1, rand2); break;
								 case 1:
										 rand3 = rand() % 9 + 1;
										 rand4 = rand() % 9 + 1;
										 printf("%d.%d/%d.%d=\t\t", rand1, rand3, rand2, rand4); break;
									 }
							 break;
			
					 case 1:
							 switch (a5)
								 {
								 case 0:printf("（%d/%d）=\t", rand1, rand2); break;
								 case 1:
										 rand3 = rand() % 9 + 1;
										 rand4 = rand() % 9 + 1;
										 printf("（%d.%d/%d.%d）=\t", rand1, rand3, rand2, rand4); break;
									 }
							 break;
						 }
			 }
	 }

	 return 0;
}