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channel _ buffering

时间:2015-03-15 16:31:15      阅读:118      评论:0      收藏:0      [点我收藏+]

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By default channels are unbuffered, meaning that they will only accept sends(chan <-) if there is a corresponding receive (<- chan) ready to receive the sent value. Buffered channels accept a limited number of values without a corresponding receiver for those values

package main

import (
    "fmt"
)

func main() {

    messages := make(chan string, 2)

    messages <- "buffered"
    messages <- "channeled"

    fmt.Println(<-messages)
    fmt.Println(<-messages)
}
buffered
channeled

总结 :

  1 : ....

channel _ buffering

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原文地址:http://www.cnblogs.com/jackkiexu/p/4339796.html

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