URAL 1823. Ideal Gas（数学啊 ）

标签：ural   数学   

题目链接：http://acm.timus.ru/problem.aspx?space=1&num=1823

1823. Ideal Gas

p = 1
n = 1
V = 1

T = 0.120279

PS:

p*V = n*R*T；

代码如下：

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const double R = 8.314;
double PP, VV, NN, TT;
void findd(char a, double b)
{
    if(a == 'p')
    {
        PP = b;
    }
    else if(a == 'V')
    {
        VV = b;
    }
    else if(a == 'n')
    {
        NN = b;
    }
    else if(a == 'T')
    {
        TT = b;
    }
}
int main()
{

    char a;
    double b;
    while(~scanf("%c = %lf",&a, &b))
    {
        getchar();
        PP = VV = NN = TT = -1;
        findd(a,b);
        scanf("%c = %lf",&a, &b);
        getchar();
        findd(a,b);
        scanf("%c = %lf",&a, &b);
        getchar();
        findd(a,b);
        if(NN < 0)
        {
            printf("n = %lf\n",(PP*VV)/(R*TT));
        }
        else if(PP < 0)
        {
            printf("p = %lf\n",(NN*R*TT)/(VV));
        }
        else if(TT < 0 || VV < 0)
        {
            if(NN==0 && PP==0)
            {
                printf("undefined\n");
            }
            else if(NN==0 || PP==0)
            {
                printf("error\n");
            }
            else if(TT < 0)
            {
                printf("T = %lf\n",(PP*VV)/(NN*R));
            }
            else if(VV < 0)
            {
                printf("V = %lf\n",(NN*R*TT)/(PP));
            }
        }
    }
    return 0;
}

URAL 1823. Ideal Gas（数学啊 ）

标签：ural   数学   

原文地址：http://blog.csdn.net/u012860063/article/details/44279393