/**
* 求平均成绩
* 第一行包含n个数据，表示n个学生的平均成绩，结果保留两位小数；
* 第二行包含m个数据，表示m门课的平均成绩，结果保留两位小数；
* 第三行是一个整数，表示该班级中各科成绩均大于等于平均成绩的学生数量
*/
import java.util.*;
public class acm2023 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (in.hasNext()) {
int n = in.nextInt();
int m = in.nextInt();
int[][] arr = new int[n][m];
double[] savg = new double[n];
double[] cavg = new double[m];
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
arr[i][j] = in.nextInt();
savg[i] += arr[i][j];
cavg[j] += arr[i][j];
}
savg[i] /= m;
}
for (int i = 0; i < m; i++) {
cavg[i] /= n;
}
for (int i = 0; i < n - 1; i++) {
System.out.printf("%.2f ", savg[i]);
}
System.out.printf("%.2f\r\n", savg[n - 1]);
for (int i = 0; i < m - 1; i++) {
System.out.printf("%.2f ", cavg[i]);
}
System.out.printf("%.2f\r\n", cavg[m - 1]);
int snum = 0;
for (int i = 0; i < n; i++) {
int flag = 1;
for (int j = 0; j < m; j++) {
if (arr[i][j] < cavg[j]) {
flag = 0;
break;
}
}
