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行列二分匹配。位于重要点的判断,删边后再判断最大匹配是否变小。
#include <cstdlib> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <fstream> #include <iostream> #define rep(i, l, r) for(int i=l; i<=r; i++) #define down(i, l, r) for(int i=l; i>=r; i--) #define N 123 #define MAX 1<<30 using namespace std; int read() { int x=0, f=1; char ch=getchar(); while (ch<‘0‘ || ch>‘9‘) { if (ch==‘-‘) f=-1; ch=getchar(); } while (ch>=‘0‘ && ch<=‘9‘) { x=x*10+ch-‘0‘; ch=getchar(); } return x*f; } struct node{int y, n; bool b;} e[N*N]; int fir[N*2], en; int n, m, c, k[N], kans[N], ans, ans2, t; bool b[N]; inline void Add(int x, int y) { en++, e[en].y=y, e[en].b=1, e[en].n=fir[x], fir[x]=en; } bool Find(int x) { int o=fir[x], y=e[o].y; while (o) { if (e[o].b && !b[y]) { b[y]=1; if (!k[y] || Find(k[y])) { k[y]=x; return true; } } o=e[o].n, y=e[o].y; } return false; } inline int Check() { rep(i, 1, n) k[i]=0; int a=0; rep(i, 1, m) { rep(j, 1, n) b[j]=0; if (Find(i+N)) a++; } return a; } int main() { while(~scanf("%d%d%d", &n, &m, &c)) { t++; ans=ans2=0; en=0; rep(i, 1, m) fir[i+N]=0; rep(i, 1, c) { int x=read(), y=read(); Add(y+N, x); } ans = Check(); rep(i, 1, n) kans[i]=k[i]; rep(i, 1, n) if (kans[i]) { int o=fir[kans[i]]; while (e[o].y != i) o=e[o].n; e[o].b=0; if (Check() != ans) ans2++; e[o].b=1; } printf("Board %d have %d important blanks for %d chessmen.\n", t, ans2, ans); } return 0; }
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原文地址:http://www.cnblogs.com/NanoApe/p/4342787.html