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This is simple, use greedy algorithm will solve the problem.
1 class Solution { 2 public: 3 int maxProfit(vector<int> &prices) { 4 int len = prices.size(), result = 0; 5 if (len < 2) return 0; 6 for (int i = 0; i < len-1; i++) { 7 if (prices[i+1] - prices[i] > 0) { 8 result += prices[i+1] - prices[i]; 9 } 10 } 11 return result; 12 } 13 };
LeetCode – Refresh – Best Time to Buy and Sell Stock ii
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原文地址:http://www.cnblogs.com/shuashuashua/p/4346163.html