The digital root of a positive integer is found by
summing the digits of the integer. If the resulting value is a single digit then
that digit is the digital root. If the resulting value contains two or more
digits, those digits are summed and the process is repeated. This is continued
as long as necessary to obtain a single digit.
For example, consider the
positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a
single digit, 6 is the digital root of 24. Now consider the positive integer 39.
Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process
must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the
digital root of 39.
The input file will contain a list of positive
integers, one per line. The end of the input will be indicated by an integer
value of zero.
For each integer in the input, output its digital root
on a separate line of the output.
We have carefully selected several similar problems for
you:
1017 1018 1048 1016 1019
//题目分析:本题重要的是对大数的境况要考虑到,利用字符数组存储大数
//在判断大数的哪一位结束时利用对位取址。还有就是求大数的根
// d%9是这个大数的根当且仅当余数是0时根为9.
#include<stdio.h>
char a[10000];
int main()
{
int d;
char *p;
while(scanf("%s",a)>0){
p=a;d=0;
while(*p){
d+=*p-‘0‘;
p++;
}
if(d==0) break;
d%=9;
if(d==0) d=9;
printf("%d\n",d);
}
return 0;
}