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【LeetCode】Rotate Array

时间:2015-03-19 13:13:02      阅读:111      评论:0      收藏:0      [点我收藏+]

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Rotate Array

Rotate an array of n elements to the right by k steps.

For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].

Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.

Credits:
Special thanks to @Freezen for adding this problem and creating all test cases.

 

AC代码:(Python)

1 class Solution:
2     # @param nums, a list of integer
3     # @param k, num of steps
4     # @return nothing, please modify the nums list in-place.
5     def rotate(self, nums, k):
6         n = len(nums)
7         k = k % n
8         nums[:] = nums[n-k:] + nums[:n-k]
9         

 

要注意一个问题:

A little important thing to be cautious:

nums[:] = nums[n-k:] + nums[:n-k] 

can‘t be written as:

nums = nums[n-k:] + nums[:n-k]

on the OJ.

The previous one can truly change the value of old nums, but the following one just changes its reference to a new nums not the value of old nums.

因为题目要求的是:

@return nothing, please modify the nums list in-place.

【LeetCode】Rotate Array

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原文地址:http://www.cnblogs.com/maples7/p/4350032.html

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