标签:
Need a corner case check for only one element [0].
1 class Solution { 2 public: 3 bool canJump(int A[], int n) { 4 if (n < 2) return true; 5 int i = 0, current = 0; 6 while (i < n) { 7 if (A[i] == 0) return false; 8 current = i + A[i]; 9 if (current >= n-1) return true; 10 for (int j = i+1, tmp = 0; j <= current; j++) { 11 if (j + A[j] > tmp) { 12 tmp = j + A[j]; 13 i = j; 14 } 15 } 16 } 17 } 18 };
LeetCode – Refresh – Jump Game
标签:
原文地址:http://www.cnblogs.com/shuashuashua/p/4352637.html