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Notes:
Do not forget to clean the total and rec.
1 class Solution { 2 public: 3 int longestValidParentheses(string s) { 4 int len = s.size(), total = 0, rec = 0, result = 0; 5 for (int i = 0; i < len; i++) { 6 if (s[i] == ‘(‘) { 7 total++; 8 rec++; 9 } else { 10 total++; 11 rec--; 12 } 13 if (rec < 0) { 14 total = 0; 15 rec = 0; 16 } else if (rec == 0) { 17 result = max(result, total); 18 } 19 } 20 total = 0, rec = 0; 21 for (int i = len-1; i >= 0; i--) { 22 if (s[i] == ‘)‘) { 23 total++; 24 rec++; 25 } else { 26 total++; 27 rec--; 28 } 29 if (rec < 0) { 30 total = 0; 31 rec = 0; 32 } else if (rec == 0) { 33 result = max(result, total); 34 } 35 } 36 return result; 37 } 38 };
LeetCode – Refresh – Longest Valid Parentheses
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原文地址:http://www.cnblogs.com/shuashuashua/p/4352706.html