Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don‘t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We‘re not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.

180 160 170

CRASH 160

#include<iostream>
int main()
{
	using namespace std;
	int n,m,k;
	while(cin>>n>>m>>k)
	{
		if(n<=168)
			cout<<"CRASH "<<n<<endl;
		if(m<=168)
			cout<<"CRASH "<<m<<endl;
		if(k<=168)
            cout<<"CRASH "<<k<<endl;
		if(n>168&&m>168&&k>168)
			cout<<"NO CRASH"<<endl;
	}
	return 0;
}