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Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 8916 Accepted Submission(s):
4056
#include<stdio.h>
#include<string.h>
int main()
{
char s1[100010];
char s2[100010];
char s3[200001];
int n,i,j,l1,l2;
while(scanf("%s\n%s",s1,s2)!=EOF)
{
l1=strlen(s1);
l2=strlen(s2);
if(l2>l1) //注意判断如果l2>l1则l2不可能包含在l1中
printf("no\n");
else
{
strcpy(s3,s1); //复制字符串
strcat(s1,s3); //拼接字符串
if(strstr(s1,s2)) //判断s2是否为s1子串
printf("yes\n");
else
printf("no\n");
}
}
return 0;
}
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原文地址:http://www.cnblogs.com/tonghao/p/4354326.html