LeetCode – Refresh – Maximum Product Subarray

 1 class Solution {
 2 public:
 3     int maxProduct(int A[], int n) {
 4         int result = A[0], gMax = A[0], gMin = A[0];
 5         for (int i = 1; i < n; i++) {
 6             int tmp = gMax;
 7             gMax = max(max(gMax*A[i], gMin*A[i]), A[i]);
 8             gMin = min(min(tmp*A[i], gMin*A[i]), A[i]);
 9             result = max(gMax, result);
10         }
11         return result;
12     }
13 };