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1 class Solution { 2 public: 3 string getRange(int start, int end) { 4 ostringstream oss; 5 if (start == end) { 6 oss << start; 7 } else { 8 oss << start << "->" << end; 9 } 10 return oss.str(); 11 } 12 vector<string> findMissingRanges(int A[], int n, int lower, int upper) { 13 vector<string> result; 14 int prev = lower - 1; 15 for (int i = 0; i < n; i++) { 16 if (A[i] - prev > 1) { 17 result.push_back(getRange(prev+1, A[i]-1)); 18 } 19 prev = A[i]; 20 } 21 if (upper - prev > 0) result.push_back(getRange(prev+1, upper)); 22 return result; 23 24 } 25 };
LeetCode – Refresh – Missing Ranges
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原文地址:http://www.cnblogs.com/shuashuashua/p/4355116.html