标签:hdoj matrix
3 3 0 0 0 1 0 1 0 1 0 0
2
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cstring>
using namespace std;
int map[110][110],vis[110];
int N,M,point[110];
bool DFS(int a){
for(int i=0;i<M;++i){
if(!vis[i]&&map[a][i]){
vis[i]=1;
if(point[i]<0||DFS(point[i])){
point[i]=a;
return true;
}
}
}
return false ;
}
int count(){
int ans=0;
for(int i=0;i<N;++i){
memset(vis,0,sizeof(vis));
if(DFS(i)){
ans++;
}
}
return ans;
}
int main()
{
int i,j;
while(scanf("%d",&N),N){
cin>>M;
memset(point,-1,sizeof(point));
memset(map,0,sizeof(map));
for(i=0;i<N;++i){
for(j=0;j<M;++j){
cin>>map[i][j];
}
}
cout<<count()<<endl;
}
return 0;
}标签:hdoj matrix
原文地址:http://blog.csdn.net/r1986799047/article/details/44497443