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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)
Total Submission(s): 9929 Accepted Submission(s): 2465

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<algorithm>
#include<cstdlib>
#include<queue>
#include<vector>
#include<stack>
using namespace std;
int n,m,sx,sy,ex,ey,ans;
int dx[4]={0,0,1,-1};
int dy[4]={1,-1,0,0};
char s[30][30];
bool vis[30][30];
struct node
{
int x,y,step;
friend bool operator<(node a,node b)
{
return a.step>b.step;
}
};
bool check(int x,int y)
{
if(x<0||y<0||x>=n||y>=m||vis[x][y]||s[x][y]==‘*‘)
return false;
return true;
}
void bfs()
{
priority_queue<node> q;
node fr;
int nx,ny;
memset(vis,0,sizeof(vis));
fr.x=sx,fr.y=sy,fr.step=0;
vis[sx][sy]=1;
q.push(fr);
while(!q.empty())
{
fr=q.top(),q.pop();
if(fr.x==ex&&fr.y==ey)
{
ans=fr.step;
break;
}
for(int i=0;i<4;i++)
{
nx=fr.x+dx[i],ny=fr.y+dy[i];
if(!check(nx,ny)) continue;
if(s[nx][ny]==‘.‘||s[nx][ny]==‘T‘)
{
node temp;
temp.x=nx,temp.y=ny;
temp.step=fr.step+1;
vis[nx][ny]=1;
q.push(temp);
}
else if(i==0||i==1)
{
if(s[nx][ny]==‘-‘&&(fr.step%2==0))
{
node temp;
nx+=dx[i],ny+=dy[i];
if(!check(nx,ny)) continue;
vis[nx][ny]=1;
temp.x=nx,temp.y=ny;
temp.step=fr.step+1;
q.push(temp);
}
else if(s[nx][ny]==‘|‘&&(fr.step%2==1))
{
node temp;
nx+=dx[i],ny+=dy[i];
if(!check(nx,ny)) continue;
vis[nx][ny]=1;
temp.x=nx,temp.y=ny;
temp.step=fr.step+1;
q.push(temp);
}
else
{
node temp;
temp.x=fr.x,temp.y=fr.y;
temp.step=fr.step+1;
q.push(temp);
}
}
else if(i==2||i==3)
{
if(s[nx][ny]==‘|‘&&(fr.step%2==0))
{
node temp;
nx+=dx[i],ny+=dy[i];
if(!check(nx,ny)) continue;
vis[nx][ny]=1;
temp.x=nx,temp.y=ny;
temp.step=fr.step+1;
q.push(temp);
}
else if(s[nx][ny]==‘-‘&&(fr.step%2==1))
{
node temp;
nx+=dx[i],ny+=dy[i];
if(!check(nx,ny)) continue;
vis[nx][ny]=1;
temp.x=nx,temp.y=ny;
temp.step=fr.step+1;
q.push(temp);
}
else
{
node temp;
temp.x=fr.x,temp.y=fr.y;
temp.step=fr.step+1;
q.push(temp);
}
}
}
}
}
int main()
{
while(scanf("%d%d",&n,&m)!=EOF)
{
for(int i=0;i<n;i++)
scanf("%s",s[i]);
for(int i=0;i<n;i++)
{
for(int j=0;j<m;j++)
{
if(s[i][j]==‘S‘)
sx=i,sy=j;
else if(s[i][j]==‘T‘)
ex=i,ey=j;
}
}
bfs();
printf("%d\n",ans);
}
return 0;
}
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原文地址:http://www.cnblogs.com/a972290869/p/4355191.html