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LeetCode - Refresh - Path Sum II

时间:2015-03-21 18:25:44      阅读:148      评论:0      收藏:0      [点我收藏+]

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Same with I

 1 /**
 2  * Definition for binary tree
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     void getSum(vector<vector<int> > &result, vector<int> current, TreeNode *root, int sum, int target) {
13         if (!root) return;
14         sum += root->val;
15         current.push_back(root->val);
16         if (!root->left && !root->right && sum == target) {
17             result.push_back(current);
18             return;
19         }
20         getSum(result, current, root->left, sum, target);
21         getSum(result, current, root->right, sum, target);
22     }
23     vector<vector<int> > pathSum(TreeNode *root, int sum) {
24         vector<vector<int> > result;
25         getSum(result, vector<int> (), root, 0, sum);
26         return result;
27     }
28 };

 

LeetCode - Refresh - Path Sum II

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原文地址:http://www.cnblogs.com/shuashuashua/p/4355903.html

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