LeetCdoe Minimum Path Sum

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Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

Note: You can only move either down or right at any point in time.

思路：简单的dp。

class Solution {
public:
    int f[1000][1000];
    int minPathSum(vector<vector<int> > &grid) {
        if (grid.size() == 0 || grid[0].size() == 0) 
            return 0;

        f[0][0] = grid[0][0];
        for (int i = 1; i < grid[0].size(); i++)
            f[0][i] = f[0][i-1] + grid[0][i];
        for (int i = 1; i < grid.size(); i++)
            f[i][0] = f[i-1][0] + grid[i][0];

        for (int i = 1; i < grid.size(); i++)
            for (int j = 1; j < grid[0].size(); j++)
                f[i][j] = min(f[i-1][j], f[i][j-1]) + grid[i][j];

        return f[grid.size()-1][grid[0].size()-1];
    }
};

LeetCdoe Minimum Path Sum

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原文地址：http://blog.csdn.net/u011345136/article/details/44698587