标签:
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 41563 Accepted Submission(s):
17414
#include<stdio.h>
int main()
{
int n,m,j,i,l;
int a[35][35];
while(scanf("%d",&n)!=EOF)
{
for(i=1;i<=n;i++) //给首尾赋值1
{
a[i][1]=1;
a[i][i]=1;
}
for(i=3;i<=n;i++)
{
for(j=2;j<i;j++)
{
a[i][j]=a[i-1][j]+a[i-1][j-1];//给出递推公式
}
}
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
if(j!=i)
printf("%d ",a[i][j]);
else
printf("%d",a[i][j]);
}
printf("\n");
}
printf("\n");
}
return 0;
}
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原文地址:http://www.cnblogs.com/tonghao/p/4373682.html