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直接用递归做了一下,超时了,可能要再加上记忆化搜索?不会...
然后再用动态规划就过了...
http://soj.sysu.edu.cn/show_problem.php?pid=1002&cid=1762
1 //直接递归,tle 2 #include <iostream> 3 #include <cstdio> 4 #include <cstring> 5 6 using namespace std; 7 8 char s1[1001]; 9 char s2[1001]; 10 11 int LCS(char s1[], char s2[], int len1, int len2) 12 { 13 if(len1 == 0 || len2 == 0) 14 return 0; 15 if(s1[len1-1] == s2[len2-1]) 16 return 1+LCS(s1, s2, len1-1, len2-1); 17 else 18 return max(LCS(s1, s2, len1-1, len2), LCS(s1, s2, len1, len2-1)); 19 } 20 21 int main() 22 { 23 while(cin >> s1 >> s2) 24 { 25 int len1 = strlen(s1); 26 int len2 = strlen(s2); 27 cout << LCS(s1, s2, len1, len2) << endl; 28 } 29 return 0; 30 }
1 //动规,思路是一样的 2 #include <iostream> 3 #include <cstring> 4 #include <cstdio> 5 6 using namespace std; 7 8 char s1[1001]; 9 char s2[1001]; 10 int dp[1001][1001]; 11 12 int LCS(char s1[], char s2[]) 13 { 14 int len1 = strlen(s1); 15 int len2 = strlen(s2); 16 memset(dp, 0, sizeof(dp)); 17 18 for(int i=1; i<=len1; i++) 19 { 20 for(int j=1; j<=len2; j++) 21 { 22 if(s1[i-1] == s2[j-1]) 23 dp[i][j] = dp[i-1][j-1] + 1; 24 else 25 dp[i][j] = max(dp[i-1][j], dp[i][j-1]); 26 } 27 } 28 return dp[len1][len2]; 29 } 30 31 int main() 32 { 33 while(cin >> s1 >> s2) 34 { 35 cout << LCS(s1, s2) << endl; 36 } 37 return 0; 38 }
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原文地址:http://www.cnblogs.com/dominjune/p/4375276.html