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三个输入框的editbox实现及测试

时间:2015-03-29 18:01:48      阅读:149      评论:0      收藏:0      [点我收藏+]

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这个星期老师要求实现并测试三个输入框的Editbox,下面是测试代码:

import java.util.regex.Matcher;
import java.util.regex.Pattern;
import javafx.application.Application;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.TextField;
import javafx.scene.layout.AnchorPane;
import javafx.scene.paint.Color;
import javafx.scene.text.Font;
import javafx.scene.text.Text;
import javafx.stage.Stage;
 
public class hahaha extends Application {
public static boolean isRegularRptCode(String rptCode,String regEx) {
Pattern pattern1 = Pattern.compile(regEx);
Matcher matcher1 = pattern1.matcher(rptCode);
boolean rs = matcher1.matches();
return rs;
}
public static void main(String[] args) {
         hahaha.launch(args);
}
public void start(Stage stage)throws Exception {
stage.setTitle("Editbox");
AnchorPane root = new AnchorPane();
Scene scene = new Scene(root, 350, 350);
scene.setFill(Color.AQUA);
Text chr1= new Text("字符串1");
chr1.setFont(new Font("宋体",  36));
AnchorPane.setTopAnchor(chr1, 25.0);
AnchorPane.setLeftAnchor(chr1, 0.0);
Text chr2= new Text("字符串2");
chr2.setFont(Font.font ("宋体", 36));
AnchorPane.setTopAnchor(chr2, 150.0);
AnchorPane.setLeftAnchor(chr2, 0.0);
Text chr3= new Text("字符串3");
chr3.setFont(Font.font ("宋体", 36));
AnchorPane.setTopAnchor(chr3, 280.0);
AnchorPane.setLeftAnchor(chr3, 0.0);
final TextField box1=new TextField();
AnchorPane.setTopAnchor(box1, 34.0);
AnchorPane.setLeftAnchor(box1, 145.0);
final TextField box2=new TextField();
AnchorPane.setTopAnchor(box2, 158.0);
AnchorPane.setLeftAnchor(box2, 145.0);
final TextField box3=new TextField();
AnchorPane.setTopAnchor(box3, 288.0);
AnchorPane.setLeftAnchor(box3, 145.0);
Button button = new Button("OK!");
AnchorPane.setTopAnchor(button, 288.0);
AnchorPane.setLeftAnchor(button, 300.0);
button.setOnAction( new EventHandler<ActionEvent>( ) {
public void handle(ActionEvent actEvt) {        
final String char1 = box1.getText();
final String char2 = box2.getText();
final String char3 = box3.getText();
if(char1.length()<1||char1.length()>6){
    System.out.println("字符串1错误");
}
else if(!isRegularRptCode(char1,"[a-z,A-Z,0-9]*")){
    System.out.println("字符串1错误");
}
else{
    System.out.println("字符串1正确");
 }
if(char2.length()<1||char2.length()>6){
    System.out.println("字符串2错误");
}
else if(!isRegularRptCode(char2,"[a-z,A-Z,0-9]*")){
    System.out.println("字符串2错误");
}
else{
    System.out.println("字符串2正确");
}
if(char3.length()<1||char3.length()>6){
    System.out.println("字符串3错误");
}
else if(!isRegularRptCode(char3,"[a-z,A-Z,0-9]*")){
    System.out.println("字符串3错误");
}
else{
    System.out.println("字符串3正确");
}                
}
} );
root.getChildren().addAll(chr1,chr2,chr3,box1,box2,box3,button);
stage.setScene(scene);
stage.show();
}
}

下面是测试界面~

技术分享

下面为测试用例以及得到的结果~

字符串1 字符串2 字符串3 测试结果
hahaha null jalifdjwjla

字符串1正确
字符串2错误
字符串3错误

hahaha xixixi aaa

字符串1正确
字符串2正确
字符串3正确

??? ?bbb ``ude

字符串1错误
字符串2错误
字符串3错误

abcdefg ABC123 19940808

字符串1错误
字符串2正确
字符串3错误

ABXK   ABC???  1?!

字符串1正确
字符串2错误
字符串3错误

下星期见~~~

三个输入框的editbox实现及测试

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原文地址:http://www.cnblogs.com/baobaoni/p/4375910.html

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