这个题目比较简单,但是有些细节。
比如:50个输入,每个都是10^9,但是奖品最高价格为5.
那么奖品5的数量将会超过int的表示范围,所以cnt要用unsigned long long类型。
#include <stdio.h>
#include <string.h>
typedef unsigned long long LL;
int n;
int points[60];
int cost[5];
LL cnt[5];
LL sum;
int main(){
freopen("input.txt","r",stdin);
while(scanf("%d",&n)!=EOF){
memset(points,0,sizeof(points));
memset(cost,0,sizeof(cost));
memset(cnt,0,sizeof(cnt));
sum=0;
for (int i = 0; i < n; ++i){
scanf("%d",&points[i]);
}
for (int i = 0; i < 5; ++i)
scanf("%d",&cost[i]);
for (int i = 0; i < n; ++i)
{
sum+=points[i];
while(sum>=cost[0]){
for (int j = 4; j >= 0; --j)
{
int num = sum/cost[j];
if (num>=1)
{
cnt[j]+=num;
sum-=cost[j]*num;
break;
}
}
}
}
printf("%llu %llu %llu %llu %llu\n",cnt[0],cnt[1],cnt[2],cnt[3],cnt[4]);
printf("%llu\n",sum);
}
}
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原文地址:http://blog.csdn.net/li8630/article/details/44737179