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这是数字转换的第一道题，要求是把阿拉伯数字转换为罗马数字，基本的思想与罗马数字转换为阿拉伯数字差不多，就是提取几个关键的数字作为比较即可。#include<stdio.h>
#include<string.h>
#include<stdlib.h>
char *link(char *s1,char *s2)
{
int len1=strlen(s1);
int len2=strlen(s2);
for(int i=len1;i<len1+len2;i++)
s1[i]=s2[i-len1];
return s1;
}
char *integerToRoman(int x)
{
char *arr[13]={"M","CM","D","CD","C","XC","L","XL","X","IX","V","IV","I"};
int value[13]= {1000,900,500,400,100,90,50,40,10,9,5,4,1};
char *roman=(char*)malloc(sizeof(char)*100);
memset(roman,0,100);
for(int i=0;x!=0;i++)
{
while(x>=value[i])
{
x-=value[i];
roman=link(roman,arr[i]);
}
}
return roman;
}
int main()
{
int x;
while(scanf("%d",&x)!=EOF)
{
printf("%s\n",integerToRoman(x));
}
return 0;
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原文地址：http://blog.csdn.net/zyh920521/article/details/44750247
