标签:
1.如下代码所示:
#include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <pthread.h> pthread_mutex_t count_lock; pthread_cond_t count_ready; int count; void *decrement_count(void *arg) { while(1) { pthread_mutex_lock(&count_lock); printf("decrement:waiting\n"); /*等待满足条件,期间互斥量仍然可用*/ // while (count == 0) pthread_cond_wait(&count_ready, &count_lock); printf("decrement:count = %d\n", count); if (count == 0) { printf("exit count:%d\n",count); exit(1); } count = 0; pthread_mutex_unlock(&count_lock); } pthread_exit(NULL); } void *increment_count(void *arg) { while(1) { pthread_mutex_lock(&count_lock); // printf("increment:running\n"); count = 1; /*通知线程条件已满足*/ // printf("increment:count = %d\n", count); pthread_cond_signal(&count_ready); pthread_mutex_unlock(&count_lock); } pthread_exit(NULL); } int main() { pthread_t tid1,tid2,tid3; count=0; pthread_mutex_init(&count_lock, NULL); pthread_cond_init(&count_ready, NULL); pthread_create(&tid1, NULL, decrement_count, NULL); sleep(3); pthread_create(&tid3, NULL, decrement_count, NULL); sleep(3); pthread_create(&tid2, NULL, increment_count, NULL); /*等待decrement退出*/ pthread_join(tid2, NULL); printf("decrement quit\n"); pthread_join(tid3, NULL); pthread_join(tid1, NULL); return 0; }
g++ -g thread-cond.cpp -lpthread -o test 编译出test程序。
然后运行,可见程序
decrement:waiting
decrement:waiting
decrement:count = 1
decrement:waiting
decrement:count = 0
exit count:0
如果把tid1,tid2,tid3表示为每个线程获得互斥锁,那么这种情况的发生说明tid1和tid3顺序获得锁执行了(顺序也可能为tid3和tid1).
单从pthread_cond_signal函数的定义上看,如果严格的只发一个"信号"给指定一个线程,这种情况是绝对不可能发生的。
因为函数中pthread_cond_wait的返回代表了此线程接受到“信号”(pthread_cond_wait执行包括1.解锁2.wait3.获得锁4.返回)
只有一个原因能解释:pthread_cond_signal一次唤醒了2个wait线程,第1个获得锁的线程把count置为0,第2个线程发现count=0直接exit,
pthread_cond_signal发生了惊群现象。
while (count == 0)
pthread_cond_wait(&count_ready, &count_lock);
在wait返回后加一个while来判断“条件”是否满足要求。
标签:
原文地址:http://www.cnblogs.com/dodng/p/4380035.html