Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
之前在Sicily做过,就是实现一个AVL树了。
struct TreeNodeNew {
int val;
TreeNodeNew *left;
TreeNodeNew *right;
int bf;
TreeNodeNew(int val = 0, TreeNodeNew * left = NULL, TreeNodeNew * right = NULL, int bf = 0) {
this->val = val;
this->left = left;
this->right = right;
this->bf = bf;
}
};
class Solution {
public:
TreeNode * sortedListToBST(ListNode * head) {
TreeNodeNew * ansNew = NULL;
ListNode * temp = head;
while (temp) {
avlInsert(ansNew, temp->val);
temp = temp->next;
}
TreeNode * ans = NULL;
if (ansNew) reBuild(ansNew, ans);
return ans;
}
void reBuild(TreeNodeNew * &nowNew, TreeNode * &now) {
now = new TreeNode(nowNew->val);
if (nowNew->left) reBuild(nowNew->left, now->left);
if (nowNew->right) reBuild(nowNew->right, now->right);
}
inline int MAX(int a, int b) {
if (a > b) return a + 1;
return b + 1;
}
void avlInsert(TreeNodeNew * &root, const int entry) {
bool unbalanced;
avlInsertInside(root, entry, unbalanced);
}
void lR(TreeNodeNew * &parent) {
TreeNodeNew * child = parent->left;
if (child->bf == 1) {
parent->left = child->right;
child->right = parent;
parent->bf = 0;
parent = child;
}
else {
TreeNodeNew * grandChild = child->right;
parent->left = grandChild->right;
child->right = grandChild->left;
grandChild->right = parent;
grandChild->left = child;
switch (grandChild->bf) {
case 0:
parent->bf = child->bf = 0;
break;
case 1:
parent->bf = -1;
child->bf = 0;
break;
case -1:
parent->bf = 0;
child->bf = 1;
}
parent = grandChild;
}
parent->bf = 0;
}
void rR(TreeNodeNew * &parent) {
TreeNodeNew * child = parent->right;
if (child->bf == -1) {
parent->right = child->left;
child->left = parent;
parent->bf = 0;
parent = child;
}
else {
TreeNodeNew * grandChild = child->left;
parent->right = grandChild->left;
child->left = grandChild->right;
grandChild->right = child;
grandChild->left = parent;
switch (grandChild->bf) {
case 0:
parent->bf = child->bf = 0;
break;
case -1:
parent->bf = 1;
child->bf = 0;
break;
case 1:
parent->bf = 0;
child->bf = -1;
}
parent = grandChild;
}
parent->bf = 0;
}
void avlInsertInside(TreeNodeNew * &parent, const int x, bool & unbalanced) {
if (parent == NULL) {
parent = new TreeNodeNew(x, 0, 0, 0);
unbalanced = true;
}
else if (x < parent->val) {
avlInsertInside(parent->left, x, unbalanced);
if (unbalanced) {
switch (parent->bf) {
case 0:
parent->bf = 1;
break;
case -1:
parent->bf = 0;
unbalanced = false;
break;
case 1:
lR(parent);
unbalanced = false;
}
}
}
else if (x > parent->val) {
avlInsertInside(parent->right, x, unbalanced);
if (unbalanced) {
switch (parent->bf) {
case 0:
parent->bf = -1;
break;
case 1:
parent->bf = 0;
unbalanced = false;
break;
case -1:
rR(parent);
unbalanced = false;
}
}
}
else {
unbalanced = false;
}
}
};LeetCode OJ Convert Sorted List to Binary Search Tree
原文地址:http://blog.csdn.net/u012925008/article/details/44781827