lua实现的大数运算,代码超短,目前只实现的加减乘运算
local mod = 10000 function add(a, b) t, c = 0, {} for i = 1, math.max(#a,#b) do t = t + (a[i] or 0) + (b[i] or 0) c[i], t = t%mod, math.floor(t/mod) end while t ~= 0 do c[#c + 1], t = t%mod, math.floor(t/mod) end return c end function sub(a, b) t, c = 0, {} for i = 1, #a do c[i] = a[i] - t - (b[i] or 0) if c[i] < 0 then t, c[i] = 1, c[i] + mod else t = 0 end end return c end function by(a, b) c = {} for i = 1, #a do t = 0 for j = 1, #b do t = t + (c[i + j - 1] or 0) + a[i] * (b[j] or 0) c[i + j - 1], t = t%mod, math.floor(t / mod) end if t ~= 0 then c[i + #b] = t + (c[i + #b] or 0) end end return c end function show(a) io.write(a[#a]) for i = #a - 1, 1, -1 do io.write(string.format("%04d", a[i])) end io.write("\n") end function input(s) n, t, a = math.floor(#s/4), 1, {} if #s%4 ~= 0 then a[n + 1], t = tonumber(string.sub(s, 1, #s%4), 10), #s%4 + 1 end for i = n, 1, -1 do a[i], t= tonumber(string.sub(s, t, t + 3), 10), t + 4 end return a end a, b = input("1434444234"), input("12") show(sub(a,b)) show(add(a,b)) show(by(a,b))
原文地址:http://blog.csdn.net/xianyun2009/article/details/44796823