Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
给定一个已排序的数组(不存在重复元素),将它转换成一棵平衡二叉搜索树。
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode *build(vector<int>&num, int low, int high){
if(low>high)return NULL;
int mid = (low+high)/2;
//生成根节点
TreeNode*root=(TreeNode*)malloc(sizeof(TreeNode));
root->val=num[mid];
//生成左子树
TreeNode*left=build(num, low, mid-1);
//生成右子树
TreeNode*right=build(num, mid+1, high);
//构造二叉树
root->left=left;
root->right=right;
return root;
}
TreeNode *sortedArrayToBST(vector<int> &num) {
int size=num.size();
if(size==0)return NULL;
return build(num, 0, size-1);
}
};LeetCode: Convert Sorted Array to Binary Search Tree [108],布布扣,bubuko.com
LeetCode: Convert Sorted Array to Binary Search Tree [108]
原文地址:http://blog.csdn.net/harryhuang1990/article/details/28384079