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You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
题意: 求上n个台阶的方法数,要么走一步,要么两步。
思路:递归超时,递推
class Solution { public: int climbStairs(int n) { if (n <= 2) return n; int f[1000]; f[1] = 1, f[2] = 2; for (int i = 3; i <= n; i++) f[i] = f[i-1] + f[i-2]; return f[n]; } };
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原文地址:http://blog.csdn.net/u011345136/article/details/44854243