LeetCode OJ Binary Tree Right Side View

标签：leetcode

Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.

For example:
Given the following binary tree,

   1            <---
 /   2     3         <---
 \       5     4       <---

You should return [1, 3, 4].

Credits:

Special thanks to @amrsaqr for adding this problem and creating all test cases.

直接优先右遍历即可，更新最大高度。

class Solution {
public:
	int depth;
	vector<int> ans;
	vector<int> rightSideView(TreeNode * root) {
		depth = -1;
		ans.clear();
		RL(root, 0);
		return ans;
	}
	void RL(TreeNode * now, int nowDepth) {
		if (!now) return;
		if (nowDepth > depth) ans.push_back(now->val), depth = nowDepth;
		RL(now->right, nowDepth + 1);
		RL(now->left, nowDepth + 1);
	}
};

LeetCode OJ Binary Tree Right Side View

标签：leetcode

原文地址：http://blog.csdn.net/u012925008/article/details/44870611