码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode Set Matrix Zeroes

时间:2015-04-04 23:47:00      阅读:163      评论:0      收藏:0      [点我收藏+]

标签:

Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.

click to show follow up.

Follow up:

Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?

题意:将0的行列置0.

思路:为了不开额外的空间,我们借助第一行和第一列,然后判断是否第一行、列也要置0

class Solution {
public: 
	void setZeroes(vector<vector<int> > &matrix) {
		int n = matrix.size();
		int m = matrix[0].size();

		bool firstRow = false, firstCol = false;
		for (int i = 0; i < n; i++) 
			if (matrix[i][0] == 0) {
				firstCol = true;
				break;
			}
		for (int i = 0; i < m; i++) 
			if (matrix[0][i] == 0) {
				firstRow = true;
				break;
			}

		for (int i = 1; i < n; i++) {
			for (int j = 1; j < m; j++) {
				if (matrix[i][j] == 0) {
					matrix[i][0] = 0;
					matrix[0][j] = 0;
				}
			}
		}

		for (int i = 1; i < n; i++) {
			if (matrix[i][0] == 0)
				for (int j = 1; j < m; j++)
					matrix[i][j] = 0;
		}
		for (int i = 1; i < m; i++) {
			if (matrix[0][i] == 0)
				for (int j = 1; j < n; j++)
					matrix[j][i] = 0;
		}

		if (firstRow) {
			for (int i = 0; i < m; i++)
				matrix[0][i] = 0;
		}
		if (firstCol) {
			for (int i = 0; i < n; i++)
				matrix[i][0] = 0;
		}
	}
};


LeetCode Set Matrix Zeroes

标签:

原文地址:http://blog.csdn.net/u011345136/article/details/44879149

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!