标签:
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
题意:将0的行列置0.
思路:为了不开额外的空间,我们借助第一行和第一列,然后判断是否第一行、列也要置0
class Solution { public: void setZeroes(vector<vector<int> > &matrix) { int n = matrix.size(); int m = matrix[0].size(); bool firstRow = false, firstCol = false; for (int i = 0; i < n; i++) if (matrix[i][0] == 0) { firstCol = true; break; } for (int i = 0; i < m; i++) if (matrix[0][i] == 0) { firstRow = true; break; } for (int i = 1; i < n; i++) { for (int j = 1; j < m; j++) { if (matrix[i][j] == 0) { matrix[i][0] = 0; matrix[0][j] = 0; } } } for (int i = 1; i < n; i++) { if (matrix[i][0] == 0) for (int j = 1; j < m; j++) matrix[i][j] = 0; } for (int i = 1; i < m; i++) { if (matrix[0][i] == 0) for (int j = 1; j < n; j++) matrix[j][i] = 0; } if (firstRow) { for (int i = 0; i < m; i++) matrix[0][i] = 0; } if (firstCol) { for (int i = 0; i < n; i++) matrix[i][0] = 0; } } };
标签:
原文地址:http://blog.csdn.net/u011345136/article/details/44879149