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[LeetCode]Unique Paths

时间:2015-04-05 17:33:39      阅读:105      评论:0      收藏:0      [点我收藏+]

标签:leetcode

题意: https://leetcode.com/problems/unique-paths/
A robot is located at the top-left corner of a m x n grid (marked ‘Start‘ in the diagram below).


The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked ‘Finish‘ in the diagram below).


How many possible unique paths are there?
思路: 简单dp 
   public int dp(int m, int n){
        if(m == 1 || n ==1) return 1;
        else return dp(m-1, n) + dp(m, n-1);
    }
纯表示一下思想,直接这么做是会超时的
那么可以把每个点到达的unique-paths数存下来
代码:
public class Solution {
    public int uniquePaths(int m, int n) {
        int pathNum = 0;
        int [][] paths = new int[m+1][n+1];
        for(int i = 1; i <= m; i ++){
            for(int j = 1; j<= n ; ++j){
                if(i == 1 || j == 1)
                    paths[i][j] = 1;
                else 
                    paths[i][j] = paths[i-1][j] + paths[i][j-1];
            }
        }
        pathNum = paths[m][n];
        return pathNum;
    }
}


[LeetCode]Unique Paths

标签:leetcode

原文地址:http://blog.csdn.net/youmengjiuzhuiba/article/details/44888755

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