For this problem,you will write a program that takes a string of characters,S,and creates a new string of characters,T,with each character repeated R times.That is,R copies of the first character of S,followed by R copies of the second character of S,and
so on.Valid characters for S are the QR
Code “alphanumeric” characters:
0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ$%*+-. /:
The first line of input contains a single integer P,(1<=P<=1000),which is the number of data sets that follow. Each data set is single line of input consisting of the data set number N,followed by a space,followed by the repeat count R,(1<=R<=8),followed by a space ,followed by the string S.The length of string S will always be at least one and no more than 20 characters.All the characters will be from the set of characters shown above.
For each data set there is one line of output. It contains the data set number,
N, followed by a single apace which is then followed by the new string T,which is made of each character in S repeated R times.
2
1 3 ABC
2 5 /HTP
1 AAABBBCCC
2 /////HHHHHTTTTTPPPPP
代码如下：
#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
int main()
{
int P,N,num;
char c[20];
cin>>P;
while (P--)
{
int i=0,j;
cin>>N>>num>>c;
cout<<N<<" ";
while(c[i]!='\0')
{
for (j=1; j<=num; j++)
{
cout<<c[i];
}
i++;
}
cout<<endl;
}
return 0;
}
运行结果：
学习心得：
我真是哔了GOU了，，，由于之前在书上看到了有一个WERTYU的字符串的题目，这次做的时候首先想的就是按照那个方法去做，结果输入3之后如果加空格了再输入ABC的话输出的结果就是1 AAABBBCCC连同这个空格一起输出了3遍，然后就开始对getchar各种处理，if(c==‘\0‘)或者&&c!=‘\0‘等等完全没有作用，反而会不再输出字符，最后抛开了那个方法用了再简单不过的cin和while(c[i]!=‘\0‘)居然直接AC了，，，字符串的输入输出上还得下狠功夫啊。这次参加ACM也有两道题就是败在了这个上面。
YTUOJ-A--A Repeating Characters
原文地址：http://blog.csdn.net/liuchang54/article/details/44919011
