标签:
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]题意:求组合。
思路:dfs搜索的类型,类似我们自己计算组合的情况,为了不重复我们必须不断的向前走
class Solution {
public:
vector<vector<int> > ans;
vector<int> tmp;
void dfs(int cur, int dep, int n, int s) {
if (cur == dep) {
ans.push_back(tmp);
return;
}
for (int i = s; i <= n; i++) {
tmp[cur] = i;
dfs(cur+1, dep, n, i+1);
}
}
vector<vector<int> > combine(int n, int k) {
tmp.resize(k);
ans.clear();
dfs(0, k, n, 1);
return ans;
}
};
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原文地址:http://blog.csdn.net/u011345136/article/details/44922319