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cpp反汇编之类和结构体分析

时间:2015-04-07 17:41:01      阅读:152      评论:0      收藏:0      [点我收藏+]

标签:cpp   反汇编   

废话不多说。。

#include<stdio.h>

class CNumber
{
public:
	CNumber()
	{
		m_nOne = 1;
		m_nTwo = 2;
	}
	int __stdcall GetNumberOne()
	{
		return m_nOne;
	}
	int GetNumberTwo()
	{
		return m_nTwo;
	}<pre name="code" class="plain">1:    #include<stdio.h>
2:
3:    class CNumber
4:    {
5:    public:
6:        CNumber()
00401060   push        ebp
00401061   mov         ebp,esp
00401063   sub         esp,44h
00401066   push        ebx
00401067   push        esi
00401068   push        edi
00401069   push        ecx
0040106A   lea         edi,[ebp-44h]
0040106D   mov         ecx,11h
00401072   mov         eax,0CCCCCCCCh
00401077   rep stos    dword ptr [edi]
00401079   pop         ecx
0040107A   mov         dword ptr [ebp-4],ecx
7:        {
8:            m_nOne = 1;
0040107D   mov         eax,dword ptr [ebp-4]
00401080   mov         dword ptr [eax],1
9:            m_nTwo = 2;
00401086   mov         ecx,dword ptr [ebp-4]
00401089   mov         dword ptr [ecx+4],2
10:       }
00401090   mov         eax,dword ptr [ebp-4]
00401093   pop         edi
00401094   pop         esi
00401095   pop         ebx
00401096   mov         esp,ebp
00401098   pop         ebp
00401099   ret

11:       int GetNumberOne()
12:       {
13:           return m_nOne;
14:       }
15:       int GetNumberTwo()
16:       {
17:           return m_nTwo;
18:       }
19:   private:
20:       int m_nOne;
21:       int m_nTwo;
22:   };
23:   int main()
24:   {
00401020   push        ebp
00401021   mov         ebp,esp
00401023   sub         esp,48h
00401026   push        ebx
00401027   push        esi
00401028   push        edi
00401029   lea         edi,[ebp-48h]
0040102C   mov         ecx,12h
00401031   mov         eax,0CCCCCCCCh
00401036   rep stos    dword ptr [edi]
25:       CNumber number;
00401038   lea         ecx,[ebp-8]
0040103B   call        @ILT+0(CNumber::CNumber) (00401005)
26:       return 0;
00401040   xor         eax,eax
27:   }
00401042   pop         edi
00401043   pop         esi
00401044   pop         ebx
00401045   add         esp,48h
00401048   cmp         ebp,esp
0040104A   call        __chkesp (004010b0)
0040104F   mov         esp,ebp
00401051   pop         ebp
00401052   ret

1:    #include<stdio.h>
2:
3:    struct A
4:    {
5:        int m_nInt;
6:        float m_fFloat;
7:    };
8:
9:    int main()
10:   {
004011A0   push        ebp
004011A1   mov         ebp,esp
004011A3   sub         esp,4Ch
004011A6   push        ebx
004011A7   push        esi
004011A8   push        edi
004011A9   lea         edi,[ebp-4Ch]
004011AC   mov         ecx,13h
004011B1   mov         eax,0CCCCCCCCh
004011B6   rep stos    dword ptr [edi]
11:       A a;
12:       A *pA = &a;
004011B8   lea         eax,[ebp-8]
004011BB   mov         dword ptr [ebp-0Ch],eax
13:       printf("%p\n" , pA);
004011BE   mov         ecx,dword ptr [ebp-0Ch]
004011C1   push        ecx
004011C2   push        offset string "%p\n" (0042601c)
004011C7   call        printf (00401210)
004011CC   add         esp,8
14:       printf("%p\n" , &pA->m_fFloat);
004011CF   mov         edx,dword ptr [ebp-0Ch]
004011D2   add         edx,4				偏移地址
004011D5   push        edx
004011D6   push        offset string "%p\n" (0042601c)
004011DB   call        printf (00401210)
004011E0   add         esp,8
15:       return 0;
004011E3   xor         eax,eax
16:   }
004011E5   pop         edi
004011E6   pop         esi
004011E7   pop         ebx
004011E8   add         esp,4Ch
004011EB   cmp         ebp,esp
004011ED   call        __chkesp (00401340)
004011F2   mov         esp,ebp
004011F4   pop         ebp
004011F5   ret

__stdcall不用ecx传递this指针,而是使用栈传递。

11:       int __stdcall GetNumberOne()
12:       {
00401160   push        ebp
00401161   mov         ebp,esp
00401163   sub         esp,40h
00401166   push        ebx
00401167   push        esi
00401168   push        edi
00401169   lea         edi,[ebp-40h]
0040116C   mov         ecx,10h
00401171   mov         eax,0CCCCCCCCh
00401176   rep stos    dword ptr [edi]
13:           return m_nOne;
00401178   mov         eax,dword ptr [ebp+8]	this
0040117B   mov         eax,dword ptr [eax]
14:       }
0040117D   pop         edi
0040117E   pop         esi
0040117F   pop         ebx
00401180   mov         esp,ebp
00401182   pop         ebp
00401183   ret         4

15:       int GetNumberTwo()
16:       {
00410AE0   push        ebp
00410AE1   mov         ebp,esp
00410AE3   sub         esp,44h
00410AE6   push        ebx
00410AE7   push        esi
00410AE8   push        edi
00410AE9   push        ecx
00410AEA   lea         edi,[ebp-44h]
00410AED   mov         ecx,11h
00410AF2   mov         eax,0CCCCCCCCh
00410AF7   rep stos    dword ptr [edi]
00410AF9   pop         ecx			this
00410AFA   mov         dword ptr [ebp-4],ecx
17:           return m_nTwo;
00410AFD   mov         eax,dword ptr [ebp-4]
00410B00   mov         eax,dword ptr [eax+4]
18:       }
00410B03   pop         edi
00410B04   pop         esi
00410B05   pop         ebx
00410B06   mov         esp,ebp
00410B08   pop         ebp
00410B09   ret

反汇编分析

1:    #include<stdio.h>
2:
3:    class CStatic
4:    {
5:    public:
6:        void ShowNumber();
7:        int m_nInt;
8:        static int m_snInt;
9:    };
10:   void CStatic :: ShowNumber()
11:   {
00401290   push        ebp
00401291   mov         ebp,esp
00401293   sub         esp,44h
00401296   push        ebx
00401297   push        esi
00401298   push        edi
00401299   push        ecx
0040129A   lea         edi,[ebp-44h]
0040129D   mov         ecx,11h
004012A2   mov         eax,0CCCCCCCCh
004012A7   rep stos    dword ptr [edi]
004012A9   pop         ecx
004012AA   mov         dword ptr [ebp-4],ecx
12:       printf("m_nInt = %d , m_snInt = %d\n" , m_nInt , m_snInt);
004012AD   mov         eax,[CStatic::m_snInt (00428a30)]
004012B2   push        eax
004012B3   mov         ecx,dword ptr [ebp-4]
004012B6   mov         edx,dword ptr [ecx]
004012B8   push        edx
004012B9   push        offset string "m_nInt = %d , m_snInt = %d\n" (00426024)
004012BE   call        printf (00401340)
004012C3   add         esp,0Ch
13:   }
004012C6   pop         edi
004012C7   pop         esi
004012C8   pop         ebx
004012C9   add         esp,44h
004012CC   cmp         ebp,esp
004012CE   call        __chkesp (00401470)
004012D3   mov         esp,ebp
004012D5   pop         ebp
004012D6   ret

14:   int CStatic::m_snInt = 9;
15:   int main()
16:   {
004012F0   push        ebp
004012F1   mov         ebp,esp
004012F3   sub         esp,44h
004012F6   push        ebx
004012F7   push        esi
004012F8   push        edi
004012F9   lea         edi,[ebp-44h]
004012FC   mov         ecx,11h
00401301   mov         eax,0CCCCCCCCh
00401306   rep stos    dword ptr [edi]
17:       CStatic sta;
18:       sta.m_nInt = 2;
00401308   mov         dword ptr [ebp-4],2
19:       sta.ShowNumber();
0040130F   lea         ecx,[ebp-4]
00401312   call        @ILT+5(CStatic::ShowNumber) (0040100a)
20:       return 0;
00401317   xor         eax,eax
21:   }
00401319   pop         edi
0040131A   pop         esi
0040131B   pop         ebx
0040131C   add         esp,44h
0040131F   cmp         ebp,esp
00401321   call        __chkesp (00401470)
00401326   mov         esp,ebp
00401328   pop         ebp
00401329   ret

1:    #include<stdio.h>
2:
3:    class CFunTest
4:    {
5:    public:
6:        int m_nOne;
7:        int m_nTwo;
8:    };
9:    void ShowFuncTest(CFunTest fun)
10:   {
00401350   push        ebp
00401351   mov         ebp,esp
00401353   sub         esp,40h
00401356   push        ebx
00401357   push        esi
00401358   push        edi
00401359   lea         edi,[ebp-40h]
0040135C   mov         ecx,10h
00401361   mov         eax,0CCCCCCCCh
00401366   rep stos    dword ptr [edi]
11:       printf("m_nOne = %d , m_nTwo = %d\n" , fun.m_nOne , fun.m_nTwo);
00401368   mov         eax,dword ptr [ebp+0Ch]
0040136B   push        eax
0040136C   mov         ecx,dword ptr [ebp+8]
0040136F   push        ecx
00401370   push        offset string "m_nOne = %d , m_nTwo = %d\n" (00426048)
00401375   call        printf (00401400)
0040137A   add         esp,0Ch
12:   }
0040137D   pop         edi
0040137E   pop         esi
0040137F   pop         ebx
00401380   add         esp,40h
00401383   cmp         ebp,esp
00401385   call        __chkesp (00401530)
0040138A   mov         esp,ebp
0040138C   pop         ebp
0040138D   ret

13:   void main()
14:   {
004013A0   push        ebp
004013A1   mov         ebp,esp
004013A3   sub         esp,48h
004013A6   push        ebx
004013A7   push        esi
004013A8   push        edi
004013A9   lea         edi,[ebp-48h]
004013AC   mov         ecx,12h
004013B1   mov         eax,0CCCCCCCCh
004013B6   rep stos    dword ptr [edi]
15:       CFunTest fun;
16:       fun.m_nOne = 9;
004013B8   mov         dword ptr [ebp-8],9
17:       fun.m_nTwo = 99;
004013BF   mov         dword ptr [ebp-4],63h
18:       ShowFuncTest(fun);
004013C6   mov         eax,dword ptr [ebp-4]
004013C9   push        eax
004013CA   mov         ecx,dword ptr [ebp-8]
004013CD   push        ecx
004013CE   call        @ILT+0(ShowFuncTest) (00401005)
004013D3   add         esp,8
19:   }
004013D6   pop         edi
004013D7   pop         esi
004013D8   pop         ebx
004013D9   add         esp,48h
004013DC   cmp         ebp,esp
004013DE   call        __chkesp (00401530)
004013E3   mov         esp,ebp
004013E5   pop         ebp
004013E6   ret


1:    #include<stdio.h>
2:    #include<string.h>
3:    class CFunTest
4:    {
5:    public:
6:        int m_nOne;
7:        int m_nTwo;
8:        char m_szName[32];
9:    };
10:   void ShowFuncTest(CFunTest fun)
11:   {
00401350   push        ebp
00401351   mov         ebp,esp
00401353   sub         esp,40h
00401356   push        ebx
00401357   push        esi
00401358   push        edi
00401359   lea         edi,[ebp-40h]
0040135C   mov         ecx,10h
00401361   mov         eax,0CCCCCCCCh
00401366   rep stos    dword ptr [edi]
12:       printf("m_nOne = %d , m_nTwo = %d , m_szName = %s\n" , fun.m_nOne , fun.m_nTwo , fun.m_szName);
00401368   lea         eax,[ebp+10h]		//m_szName
0040136B   push        eax
0040136C   mov         ecx,dword ptr [ebp+0Ch]	//m_nTwo
0040136F   push        ecx
00401370   mov         edx,dword ptr [ebp+8]	//m_nOne
00401373   push        edx
00401374   push        offset string "m_nOne = %d , m_nTwo = %d , m_sz"... (00427050)
00401379   call        printf (00401400)
0040137E   add         esp,10h
13:   }
00401381   pop         edi
00401382   pop         esi
00401383   pop         ebx
00401384   add         esp,40h
00401387   cmp         ebp,esp
00401389   call        __chkesp (00401530)
0040138E   mov         esp,ebp
00401390   pop         ebp
00401391   ret

14:   void main()
15:   {
004013A0   push        ebp
004013A1   mov         ebp,esp
004013A3   sub         esp,68h
004013A6   push        ebx
004013A7   push        esi
004013A8   push        edi
004013A9   lea         edi,[ebp-68h]
004013AC   mov         ecx,1Ah
004013B1   mov         eax,0CCCCCCCCh
004013B6   rep stos    dword ptr [edi]
16:       CFunTest fun;
17:       fun.m_nOne = 9;
004013B8   mov         dword ptr [ebp-28h],9
18:       fun.m_nTwo = 99;
004013BF   mov         dword ptr [ebp-24h],63h
19:       strcpy(fun.m_szName , "NAME");
004013C6   push        offset string "NAME" (00426040)
004013CB   lea         eax,[ebp-20h]		ebp-32  m_szName
004013CE   push        eax
004013CF   call        strcpy (00407c80)
20:       ShowFuncTest(fun);
004013D4   add         esp,0E0h		//sub esp , 68h  add esp , 0e0h
004013D7   mov         ecx,0Ah
004013DC   lea         esi,[ebp-28h]
004013DF   mov         edi,esp
004013E1   rep movs    dword ptr [edi],dword ptr [esi]	40BYTE
004013E3   call        @ILT+0(ShowFuncTest) (00401005)
004013E8   add         esp,28h		40BYTE
21:   }
004013EB   pop         edi
004013EC   pop         esi
004013ED   pop         ebx
004013EE   add         esp,68h
004013F1   cmp         ebp,esp
004013F3   call        __chkesp (00401530)
004013F8   mov         esp,ebp
004013FA   pop         ebp
004013FB   ret

004013D4   add         esp,0E0h
004013D7   mov         ecx,0Ah
004013DC   lea         esi,[ebp-28h]
004013DF   mov         edi,esp		edi即是esp栈顶  此处进行值传递
004013E1   rep movs    dword ptr [edi],dword ptr [esi]
004013E3   call        @ILT+0(ShowFuncTest) (00401005)
004013E8   add         esp,28h

 EAX = 0018FF28 EBX = 7EFDE000
 ECX = 00000000 EDX = 00000000
 ESI = 0018FF48 EDI = 0018FED4
 EIP = 004013E3 ESP = 0018FEAC
 EBP = 0018FF48 EFL = 00000207


0018FEAC  09 00 00 00 63 00 00 00 4E 41 4D  ...c...NAM
0018FEB7  45 00 CC CC CC CC CC CC CC CC CC  E.烫烫烫烫.
0018FEC2  CC CC CC CC CC CC CC CC CC CC CC  烫烫烫烫烫.
0018FECD  CC CC CC CC CC CC CC 00 00 00 00  烫烫烫.....
0018FED8  00 00 00 00 00 E0 FD 7E CC CC CC  .....帻~烫.
0018FEE3  CC CC CC CC CC CC CC CC CC CC CC  烫烫烫烫烫.


private:int m_nOne;int m_nTwo;};struct tagTest{char m_cChar;double m_dDouble;int m_nInt;float m_fFloat;};int main1(){CNumber number;printf("%d\n" , number.GetNumberOne());printf("%d\n" , number.GetNumberTwo());tagTest tag;tag.m_dDouble = 1.0;printf("%d\n" , sizeof(tagTest));printf("%p\n" , &tag.m_cChar);printf("%p\n" , &tag.m_dDouble);printf("%p\n" , &tag.m_nInt);printf("%p\n" , &tag.m_fFloat);return 0;}



另一个例子

#include<stdio.h>

class CReturn 
{
public:
	int m_nNumber;
	int m_nArray[10];
};
CReturn GetReturn()
{
	CReturn ret;
	ret.m_nNumber = 0;
	for(int i = 0; i < 10; ++i)
	{
		ret.m_nArray[i] = i + 1;
	}
	return ret;
}
void main()
{
	CReturn objA;
	objA = GetReturn();
	printf("%d %d %d\n" , objA.m_nNumber , objA.m_nArray[0] , objA.m_nArray[9]);
	
}

反汇编分析

1:    #include<stdio.h>
2:
3:    class CReturn
4:    {
5:    public:
6:        int m_nNumber;
7:        int m_nArray[10];
8:    };
9:    CReturn GetReturn()
10:   {
004016F0   push        ebp	ebp=ebp0-2ch-8h
004016F1   mov         ebp,esp
004016F3   sub         esp,70h
004016F6   push        ebx
004016F7   push        esi
004016F8   push        edi
004016F9   lea         edi,[ebp-70h]
004016FC   mov         ecx,1Ch
00401701   mov         eax,0CCCCCCCCh
00401706   rep stos    dword ptr [edi]
11:       CReturn ret;
12:       ret.m_nNumber = 0;
00401708   mov         dword ptr [ebp-2Ch],0
13:       for(int i = 0; i < 10; ++i)
0040170F   mov         dword ptr [ebp-30h],0	i
00401716   jmp         GetReturn+31h (00401721)
00401718   mov         eax,dword ptr [ebp-30h]
0040171B   add         eax,1
0040171E   mov         dword ptr [ebp-30h],eax
00401721   cmp         dword ptr [ebp-30h],0Ah	i < 10
00401725   jge         GetReturn+46h (00401736)
14:       {
15:           ret.m_nArray[i] = i + 1;
00401727   mov         ecx,dword ptr [ebp-30h]
0040172A   add         ecx,1
0040172D   mov         edx,dword ptr [ebp-30h]
00401730   mov         dword ptr [ebp+edx*4-28h],ecx	//m_nArray[i] = i + 1
16:       }
00401734   jmp         GetReturn+28h (00401718)
17:       return ret;
00401736   mov         ecx,0Bh			//0B 11 44字节
0040173B   lea         esi,[ebp-2Ch]
0040173E   mov         edi,dword ptr [ebp+8]	//传送数据  返回值
00401741   rep movs    dword ptr [edi],dword ptr [esi]
00401743   mov         eax,dword ptr [ebp+8]
18:   }
00401746   pop         edi
00401747   pop         esi
00401748   pop         ebx
00401749   mov         esp,ebp
0040174B   pop         ebp
0040174C   ret

19:   void main()
20:   {
00401770   push        ebp
00401771   mov         ebp,esp
00401773   sub         esp,0C4h			//预留栈空间  12*16+4
00401779   push        ebx
0040177A   push        esi
0040177B   push        edi
0040177C   lea         edi,[ebp-0C4h]
00401782   mov         ecx,31h
00401787   mov         eax,0CCCCCCCCh
0040178C   rep stos    dword ptr [edi]
21:       CReturn objA;				//44  11*4 2ch  ebp-2ch
22:       objA = GetReturn();
0040178E   lea         eax,[ebp-84h]		//8*16+4 44+44
00401794   push        eax			//返回地址压栈
00401795   call        @ILT+45(GetReturn) (00401032)	
0040179A   add         esp,4			//eax栈平衡
0040179D   mov         esi,eax			//返回值地址
0040179F   mov         ecx,0Bh
004017A4   lea         edi,[ebp-58h]
004017A7   rep movs    dword ptr [edi],dword ptr [esi]	//传送至临时对象  临时对象释放时,可能存在多次释放资源现象。
004017A9   mov         ecx,0Bh
004017AE   lea         esi,[ebp-58h]		
004017B1   lea         edi,[ebp-2Ch]
004017B4   rep movs    dword ptr [edi],dword ptr [esi]
23:       printf("%d %d %d\n" , objA.m_nNumber , objA.m_nArray[0] , objA.m_nArray[9]);
004017B6   mov         ecx,dword ptr [ebp-4]
004017B9   push        ecx
004017BA   mov         edx,dword ptr [ebp-28h]
004017BD   push        edx
004017BE   mov         eax,dword ptr [ebp-2Ch]
004017C1   push        eax
004017C2   push        offset string "%d %d %d\n" (00429090)
004017C7   call        printf (00401800)
004017CC   add         esp,10h
24:
25:   }
004017CF   pop         edi
004017D0   pop         esi
004017D1   pop         ebx
004017D2   add         esp,0C4h
004017D8   cmp         ebp,esp
004017DA   call        __chkesp (00401930)
004017DF   mov         esp,ebp
004017E1   pop         ebp
004017E2   ret

例子

#include<stdio.h>
#include<string.h>

class CMyString
{
public:
	CMyString()
	{
		m_pString = new char[10];
		if(NULL == m_pString)
		{
			return ;
		}
		strcpy(m_pString , "Hello");
	}
	~CMyString()
	{
		if(m_pString != NULL)
		{
			delete [] m_pString;
			m_pString = NULL;
		}
	}
	char * GetString()
	{
		return m_pString;
	}
private:
	char *m_pString;
};

void ShowMyString(CMyString str)
{
	printf("%s\n" , str.GetString());
}
int main5()
{
	CMyString str;
	ShowMyString(str);	//
	return 0;
}

反汇编分析

1:    #include<stdio.h>
2:    #include<string.h>
3:
4:    class CMyString
5:    {
6:    public:
7:        CMyString()
00401660   push        ebp
00401661   mov         ebp,esp
00401663   sub         esp,48h
00401666   push        ebx
00401667   push        esi
00401668   push        edi
00401669   push        ecx
0040166A   lea         edi,[ebp-48h]
0040166D   mov         ecx,12h
00401672   mov         eax,0CCCCCCCCh
00401677   rep stos    dword ptr [edi]
00401679   pop         ecx
0040167A   mov         dword ptr [ebp-4],ecx
8:        {
9:            m_pString = new char[10];
0040167D   push        0Ah
0040167F   call        operator new (00401ea0)
00401684   add         esp,4
00401687   mov         dword ptr [ebp-8],eax
0040168A   mov         eax,dword ptr [ebp-4]
0040168D   mov         ecx,dword ptr [ebp-8]
00401690   mov         dword ptr [eax],ecx
10:           if(NULL == m_pString)
00401692   mov         edx,dword ptr [ebp-4]
00401695   cmp         dword ptr [edx],0
00401698   jne         CMyString::CMyString+3Ch (0040169c)
11:           {
12:               return ;
0040169A   jmp         CMyString::CMyString+4Fh (004016af)
13:           }
14:           strcpy(m_pString , "Hello");
0040169C   push        offset string "Hello" (00429088)
004016A1   mov         eax,dword ptr [ebp-4]
004016A4   mov         ecx,dword ptr [eax]
004016A6   push        ecx
004016A7   call        strcpy (00401850)
004016AC   add         esp,8
15:       }
004016AF   mov         eax,dword ptr [ebp-4]
004016B2   pop         edi
004016B3   pop         esi
004016B4   pop         ebx
004016B5   add         esp,48h
004016B8   cmp         ebp,esp
004016BA   call        __chkesp (00401810)
004016BF   mov         esp,ebp
004016C1   pop         ebp
004016C2   ret

16:       ~CMyString()
17:       {
00401510   push        ebp
00401511   mov         ebp,esp
00401513   sub         esp,48h
00401516   push        ebx
00401517   push        esi
00401518   push        edi
00401519   push        ecx
0040151A   lea         edi,[ebp-48h]
0040151D   mov         ecx,12h
00401522   mov         eax,0CCCCCCCCh
00401527   rep stos    dword ptr [edi]
00401529   pop         ecx
0040152A   mov         dword ptr [ebp-4],ecx
18:           if(m_pString != NULL)
0040152D   mov         eax,dword ptr [ebp-4]
00401530   cmp         dword ptr [eax],0
00401533   je          CMyString::~CMyString+42h (00401552)
19:           {
20:               delete [] m_pString;
00401535   mov         ecx,dword ptr [ebp-4]
00401538   mov         edx,dword ptr [ecx]
0040153A   mov         dword ptr [ebp-8],edx
0040153D   mov         eax,dword ptr [ebp-8]
00401540   push        eax
00401541   call        operator delete (00401e10)
00401546   add         esp,4
21:               m_pString = NULL;
00401549   mov         ecx,dword ptr [ebp-4]
0040154C   mov         dword ptr [ecx],0
22:           }
23:       }
00401552   pop         edi
00401553   pop         esi
00401554   pop         ebx
00401555   add         esp,48h
00401558   cmp         ebp,esp
0040155A   call        __chkesp (00401810)
0040155F   mov         esp,ebp
00401561   pop         ebp
00401562   ret

24:       char * GetString()
25:       {
00401580   push        ebp
00401581   mov         ebp,esp
00401583   sub         esp,44h
00401586   push        ebx
00401587   push        esi
00401588   push        edi
00401589   push        ecx
0040158A   lea         edi,[ebp-44h]
0040158D   mov         ecx,11h
00401592   mov         eax,0CCCCCCCCh
00401597   rep stos    dword ptr [edi]
00401599   pop         ecx
0040159A   mov         dword ptr [ebp-4],ecx
26:           return m_pString;
0040159D   mov         eax,dword ptr [ebp-4]	eax相当于二维指针
004015A0   mov         eax,dword ptr [eax]
27:       }
004015A2   pop         edi
004015A3   pop         esi
004015A4   pop         ebx
004015A5   mov         esp,ebp
004015A7   pop         ebp
004015A8   ret

28:   private:
29:       char *m_pString;
30:   };
31:
32:   void ShowMyString(CMyString str)
33:   {
00401470   push        ebp
00401471   mov         ebp,esp
00401473   push        0FFh
00401475   push        offset __ehhandler$?ShowMyString@@YAXVCMyString@@@Z (00417769)
0040147A   mov         eax,fs:[00000000]
00401480   push        eax
00401481   mov         dword ptr fs:[0],esp
00401488   sub         esp,40h
0040148B   push        ebx
0040148C   push        esi
0040148D   push        edi
0040148E   lea         edi,[ebp-4Ch]
00401491   mov         ecx,10h
00401496   mov         eax,0CCCCCCCCh
0040149B   rep stos    dword ptr [edi]
0040149D   mov         dword ptr [ebp-4],0
34:       printf("%s\n" , str.GetString());
004014A4   lea         ecx,[ebp+8]
004014A7   call        @ILT+0(CMyString::GetString) (00401005)		ECX = 0018FEE4
004014AC   push        eax
004014AD   push        offset string "%s\n" (00429084)
004014B2   call        printf (004016e0)
004014B7   add         esp,8
35:   }
004014BA   mov         dword ptr [ebp-4],0FFFFFFFFh
004014C1   lea         ecx,[ebp+8]					ECX = 0018FEE4
004014C4   call        @ILT+60(CMyString::~CMyString) (00401041)	//释放资源
004014C9   mov         ecx,dword ptr [ebp-0Ch]
004014CC   mov         dword ptr fs:[0],ecx
004014D3   pop         edi
004014D4   pop         esi
004014D5   pop         ebx
004014D6   add         esp,4Ch
004014D9   cmp         ebp,esp
004014DB   call        __chkesp (00401810)
004014E0   mov         esp,ebp
004014E2   pop         ebp
004014E3   ret

36:   int main()
37:   {
004015C0   push        ebp
004015C1   mov         ebp,esp
004015C3   push        0FFh
004015C5   push        offset __ehhandler$_main (00417789)
004015CA   mov         eax,fs:[00000000]
004015D0   push        eax
004015D1   mov         dword ptr fs:[0],esp
004015D8   sub         esp,48h
004015DB   push        ebx
004015DC   push        esi
004015DD   push        edi
004015DE   lea         edi,[ebp-54h]
004015E1   mov         ecx,12h
004015E6   mov         eax,0CCCCCCCCh
004015EB   rep stos    dword ptr [edi]
38:       CMyString str;
004015ED   lea         ecx,[ebp-10h]
004015F0   call        @ILT+30(CMyString::CMyString) (00401023)
004015F5   mov         dword ptr [ebp-4],0
39:       ShowMyString(str);  //
004015FC   mov         eax,dword ptr [ebp-10h]
004015FF   push        eax
00401600   call        @ILT+55(ShowMyString) (0040103c)
00401605   add         esp,4
40:       return 0;
00401608   mov         dword ptr [ebp-14h],0
0040160F   mov         dword ptr [ebp-4],0FFFFFFFFh
00401616   lea         ecx,[ebp-10h]
00401619   call        @ILT+60(CMyString::~CMyString) (00401041)	 ECX = 0018FF38 
0040161E   mov         eax,dword ptr [ebp-14h]
41:   }
00401621   mov         ecx,dword ptr [ebp-0Ch]
00401624   mov         dword ptr fs:[0],ecx
0040162B   pop         edi
0040162C   pop         esi
0040162D   pop         ebx
0040162E   add         esp,54h
00401631   cmp         ebp,esp
00401633   call        __chkesp (00401810)
00401638   mov         esp,ebp
0040163A   pop         ebp
0040163B   ret

ShowMyString EAX = 00713A48 == [ebp - 10h]

00713A48  48 65 6C 6C 6F 00 CD CD CD CD FD  Hello.屯屯.
00713A53  FD FD FD AD BA AB AB AB AB AB AB  韩.
00713A5E  AB AB 00 00 00 00 00 00 00 00 D8  .........
00713A69  47 B3 B5 B1 93 00 00 08 0F 71 00  G车睋....q.
00713A74  C4 00 71 00 EE FE EE FE EE FE EE  ..q.铪铪铪.
00713A7F  FE EE FE EE FE EE FE EE FE EE FE  .

lea         ecx,[ebp+8]		ECX = 0018FEE4
0040159A   mov         dword ptr [ebp-4],ecx	 ECX = 0018FEE4
EBP = 0018FEDC
0018FED1  FF 18 00 69 77 41 00 00 00 00 00  ...iwA.....
0018FEDC  48 FF 18 00 05 16 40 00 48 3A 71  H.....@.H:q
0018FEE7  00 00 00 00 00 00 00 00 00 00 E0  ...........
0040152A   mov         dword ptr [ebp-4],ecx	 ECX = 0018FEE4

 EAX = 0018FEE4 EBX = 7EFDE000
 ECX = 0018FEE4 EDX = 0042BCA0
 ESI = 00000000 EDI = 0018FE7C
 EIP = 00401538 ESP = 0018FE28
 EBP = 0018FE7C EFL = 00000206

00401535   mov         ecx,dword ptr [ebp-4]
00401538   mov         edx,dword ptr [ecx]
0040153A   mov         dword ptr [ebp-8],edx
0040153D   mov         eax,dword ptr [ebp-8]
00401540   push        eax
00401541   call        operator delete (00401e10)
00401546   add         esp,4

0018FE63  CC CC CC CC CC CC CC CC CC CC CC  烫烫烫烫烫.
0018FE6E  CC CC CC CC CC CC CC CC CC CC E4  烫烫烫烫烫.
0018FE79  FE 18 00 DC FE 18 00 C9 14 40 00  ...荥....@.
0018FE84  3C FF 18 00 00 00 00 00 00 E0 FD  <........帻
0018FE8F  7E CC CC CC CC CC CC CC CC CC CC  ~烫烫烫烫烫

0018FE63  CC CC CC CC CC CC CC CC CC CC CC  烫烫烫烫烫.
0018FE6E  CC CC CC CC CC CC 48 3A 71 00 E4  烫烫烫H:q..
0018FE79  FE 18 00 DC FE 18 00 C9 14 40 00  ...荥....@.
0018FE84  3C FF 18 00 00 00 00 00 00 E0 FD  <........帻

0018FE6E  CC CC CC CC CC CC 48 3A 71 00 E4  烫烫烫H:q..
0018FE79  FE 18 00 DC FE 18 00 C9 14 40 00  ...荥....@.
0018FE84  3C FF 18 00 00 00 00 00 00 E0 FD  <........帻

 EAX = 00000001 EBX = 7EFDE000
 ECX = 0018FF3C EDX = 0071015C
 ESI = 00000000 EDI = 0018FF3C
 EIP = 00401616 ESP = 0018FEE8
 EBP = 0018FF48 EFL = 00000206

40:       return 0;
00401608   mov         dword ptr [ebp-14h],0
0040160F   mov         dword ptr [ebp-4],0FFFFFFFFh
00401616   lea         ecx,[ebp-10h]
00401619   call        @ILT+60(CMyString::~CMyString) (00401041)
0040161E   mov         eax,dword ptr [ebp-14h]
41:   }

 EAX = 00000001 EBX = 7EFDE000
 ECX = 0018FF38 EDX = 0071015C
 ESI = 00000000 EDI = 0018FF3C
 EIP = 00401619 ESP = 0018FEE8
 EBP = 0018FF48 EFL = 00000206

00401529   pop         ecx
0040152A   mov         dword ptr [ebp-4],ecx
18:           if(m_pString != NULL)
0040152D   mov         eax,dword ptr [ebp-4]
00401530   cmp         dword ptr [eax],0
00401533   je          CMyString::~CMyString+42h (00401552)
19:           {
20:               delete [] m_pString;
00401535   mov         ecx,dword ptr [ebp-4]
00401538   mov         edx,dword ptr [ecx]
0040153A   mov         dword ptr [ebp-8],edx
0040153D   mov         eax,dword ptr [ebp-8]
00401540   push        eax
00401541   call        operator delete (00401e10)
00401546   add         esp,4
21:               m_pString = NULL;
00401549   mov         ecx,dword ptr [ebp-4]
0040154C   mov         dword ptr [ecx],0
22:           }
23:       }

 EAX = CCCCCCCC EBX = 7EFDE000
 ECX = 0018FF38 EDX = 0071015C
 ESI = 00000000 EDI = 0018FEE0
 EIP = 0040152A ESP = 0018FE8C
 EBP = 0018FEE0 EFL = 00000212

00401535   mov         ecx,dword ptr [ebp-4]

 EAX = 0018FF38 EBX = 7EFDE000
 ECX = 0018FF38 EDX = 0071015C
 ESI = 00000000 EDI = 0018FEE0
 EIP = 00401538 ESP = 0018FE8C
 EBP = 0018FEE0 EFL = 00000206
00401538   mov         edx,dword ptr [ecx]
 EAX = 0018FF38 EBX = 7EFDE000
 ECX = 0018FF38 EDX = 00713A48
 ESI = 00000000 EDI = 0018FEE0
 EIP = 0040153A ESP = 0018FE8C
 EBP = 0018FEE0 EFL = 00000206

00401540   push        eax
00401541   call        operator delete (00401e10)
 EAX = 00713A48 EBX = 7EFDE000
 ECX = 0018FF38 EDX = 00713A48
 ESI = 00000000 EDI = 0018FEE0
 EIP = 00401541 ESP = 0018FE88
 EBP = 0018FEE0 EFL = 00000206


cpp反汇编之类和结构体分析

标签:cpp   反汇编   

原文地址:http://blog.csdn.net/u011185633/article/details/44922215

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