标签:
Given a set of distinct integers, S, return all possible subsets.
Note:
For example,
If S = [1,2,3],
a solution is:
[ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ]题意:求数组子集。
思路:一个dfs,取与不取;一个是二进制可以代表所有的子集。
class Solution {
public:
vector<vector<int> > ans;
void subCal(vector<int> &S, int cur, vector<int> v) {
if (cur == S.size()) {
ans.push_back(v);
return;
}
subCal(S, cur+1, v);
v.push_back(S[cur]);
subCal(S, cur+1, v);
}
vector<vector<int> > subsets(vector<int> &S) {
vector<int> v;
sort(S.begin(), S.end());
subCal(S, 0, v);
return ans;
}
};class Solution {
public:
vector<vector<int> > subsets(vector<int> &S) {
sort(S.begin(), S.end());
int n = S.size();
int Max = 1<<n;
vector<vector<int> > ans;
for (int i = 0; i < Max; i++) {
vector<int> tmp;
int cur = i;
int indx = 0;
while (cur > 0) {
if (cur & 1)
tmp.push_back(S[indx]);
indx++;
cur = cur >> 1;
}
ans.push_back(tmp);
}
return ans;
}
};标签:
原文地址:http://blog.csdn.net/u011345136/article/details/44925791