输入格式
输出格式
共n-1行,第i行表示1号点到i+1号点的最短路。
样例输入
3 3
样例输出
-1
数据规模与约定
题目链接:http://lx.lanqiao.org/problem.page?gpid=T15
题目分析:再记一下SPFA的vector版的板子
#include <cstdio>
#include <cstring>
#include <queue>
#include <vector>
using namespace std;
int const MAX = 200005;
int const INF = 1 << 30;
int n, m;
struct EDGE
{
int u, v;
int val;
}e[MAX << 2];
struct NODE
{
int v, w;
NODE(int vv, int ww)
{
v = vv;
w = ww;
}
};
vector <NODE> vt[MAX];
int dis[MAX];
bool vis[MAX];
void SPFA(int v0)
{
memset(vis, false, sizeof(vis));
for(int i = 1; i <= n; i++)
dis[i] = INF;
dis[v0] = 0;
queue <int> q;
q.push(v0);
while(!q.empty())
{
int u = q.front();
q.pop();
vis[u] = false;
int sz = vt[u].size();
for(int i = 0; i < sz; i++)
{
int v = vt[u][i].v;
int w = vt[u][i].w;
if(dis[v] > dis[u] + w)
{
dis[v] = dis[u] + w;
if(!vis[v])
{
q.push(v);
vis[v] = true;
}
}
}
}
}
int main()
{
scanf("%d %d", &n, &m);
for(int i = 0; i < m; i++)
scanf("%d %d %d", &e[i].u, &e[i].v, &e[i].val);
for(int i = 0; i < m; i++)
vt[e[i].u].push_back(NODE(e[i].v, e[i].val));
SPFA(1);
for(int i = 2; i <= n; i++)
printf("%d\n", dis[i]);
}原文地址:http://blog.csdn.net/tc_to_top/article/details/44935507