#define X 5即可测试任何阶马踏棋盘游戏,阶数越高,程序运行时间将会越长。(8阶都不知道要跑到什么时候。。)
void CHorse::funcStart() { funcTravel(0, 0, nStep); }
#include <stdio.h> #include <iostream> #define X 5 using namespace std; static int nChess[X][X] = {0}; class CHorse { public: CHorse(); // 构造函数 void funcStart(); // 开始行走 void funcCout(); // 打印棋盘 void funcTravel(int x, int y, int n); // 从点<x,y>继续行走 bool funcNextStep(int *x, int *y, int z); // 寻找下一步可行点 int funcGetnCount(); // 获取nCount private: static int nCount; // 统计总共的可行方案数 }; int CHorse::nCount = 0; CHorse::CHorse() { } int CHorse::funcGetnCount() { return nCount; } void CHorse::funcStart() { funcTravel(0, 0, 1); } void CHorse::funcTravel(int x, int y, int n) { int nTraveli, nX1=x, nY1=y; nChess[x][y] = n; if( n==X*X ) { // 棋盘遍历完毕 funcCout(); } else { // 循环遍历周边8个可行方案 for(nTraveli=0; nTraveli<8; nTraveli++) { if( funcNextStep(&nX1, &nY1, nTraveli) ) { funcTravel(nX1, nY1, n+1); nChess[nX1][nY1] = 0; nX1 = x; nY1 = y; } } } } bool CHorse::funcNextStep(int *x, int *y, int z) { switch(z) { case 0: if( *x>1 && *y>0 && nChess[*x-2][*y-1]==0 ) { *x = *x-2; *y = *y-1; return true; } break; case 1: if( *x<X-2 && *y>0 && nChess[*x+2][*y-1]==0 ) { *x = *x+2; *y = *y-1; return true; } break; case 2: if( *x>1 && *y<X-1 && nChess[*x-2][*y+1]==0 ) { *x = *x-2; *y = *y+1; return true; } break; case 3: if( *x<X-2 && *y<X-1 && nChess[*x+2][*y+1]==0 ) { *x = *x+2; *y = *y+1; return true; } break; case 4: if( *x>0 && *y>1 && nChess[*x-1][*y-2]==0 ) { *x = *x-1; *y = *y-2; return true; } break; case 5: if( *x<X-1 && *y>1 && nChess[*x+1][*y-2]==0 ) { *x = *x+1; *y = *y-2; return true; } break; case 6: if( *x>0 && *y<X-2 && nChess[*x-1][*y+2]==0 ) { *x = *x-1; *y = *y+2; return true; } break; case 7: if( *x<X-1 && *y<X-2 && nChess[*x+1][*y+2]==0 ) { *x = *x+1; *y = *y+2; return true; } break; } return false; } void CHorse::funcCout() { int i, j; nCount++; for(i=0; i<X; i++) { for(j=0; j<X; j++) { printf("%-4d", nChess[i][j]); } printf("\n"); } printf("\n\n"); } void main() { int n; CHorse objHorse; objHorse.funcStart(); printf("::马踏棋盘游戏::以<0,0>为起点的5阶棋盘共有%d种走法\n\n", objHorse.funcGetnCount()); }
原文地址:http://blog.csdn.net/bigric3/article/details/44937923