标签:
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 19396 Accepted Submission(s): 8246
#include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<queue> using namespace std; int n,m,k; int u[5000],v[5000]; int w[5000]; int r[5000],p[105]; int cmp(const int i,const int j)//对w[]间接排序 { return w[i]<w[j]; } void read_graph()//图存储 { for(int i=0;i<n;++i) cin>>u[i]>>v[i]>>w[i]; } int find(int x)//并查集查找函数 { return p[x]==x?x:p[x]=find(p[x]); } void kruskal() { read_graph(); for(int i=0;i<=m;++i) p[i]=i; for(int i=0;i<=n;++i) r[i]=i; sort(r,r+n,cmp); int ans=0; for(int i=0;i<n;++i){ int e=r[i]; int x=find(u[e]); int y=find(v[e]); if(x!=y) {ans+=w[e];p[y]=x;} } int cnt=0; for(int i=1;i<=m;++i) if(p[i]==i) cnt++;//计算连通分支个数 if(cnt!=1) cout<<‘?‘<<endl;//连通分支数为1时才满足条件 else cout<<ans<<endl; } int main() { while(scanf("%d%d",&n,&m)&&n) kruskal(); return 0; }
标签:
原文地址:http://www.cnblogs.com/orchidzjl/p/4404240.html