2014年6月7日04:23:23

 1             //将一个字符串数组的元素的顺序进行反转。{"3","a","8","haha"} {"haha","8","a","3"}。第i个和第length-i-1个进行交换。
 2             string[] strs = { "3", "a", "8", "haha" };
 3             for (int i = 0; i < strs.Length / 2; i++)
 4             {
 5                 //i,len-1-i
 6                 //交换两个元素，想像一下交换i，j，交换两个杯子中的水
 7                 string temp = strs[i];
 8                 strs[i] = strs[strs.Length - 1 - i];
 9                 strs[strs.Length - 1 - i] = temp;
10             }
11 
12             for (int i = 0; i < strs.Length; i++)
13             {
14                 Console.Write(strs[i]+",");
15             }