码迷,mamicode.com
首页 > 其他好文 > 详细

Sum Root to Leaf Numbers--LeetCode

时间:2015-04-09 11:51:56      阅读:161      评论:0      收藏:0      [点我收藏+]

标签:c++   leetcode   算法   

题目:

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1
   /   2   3

The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

思路:如果知道从根节点到所有叶子节点的路径上的数字,然后将这条路径转换为整数,将所有的路径转换的整数相加,就是所求的结果

void helper_leaf(BinTree* root,vector<int>& path,int& sum)
{
	if(root == NULL)
		return ;
	path.push_back(root->value);
	if(root->left == NULL && root->right == NULL)
	{
		int tmp=0;
		for(int i=0;i<path.size();i++)
			tmp = tmp*10 + path[i];
		sum += tmp;
	//	cout<<"tmp is "<<tmp<<endl; 
		//return ;
	}
	
	helper_leaf(root->left,path,sum);
	helper_leaf(root->right,path,sum);
	path.pop_back();
}

int RootToLeaf(BinTree* root)
{
	if(root == NULL)
		return 0;
	vector<int> path;
	int sum=0;
	helper_leaf(root,path,sum);
	return sum;
}




Sum Root to Leaf Numbers--LeetCode

标签:c++   leetcode   算法   

原文地址:http://blog.csdn.net/yusiguyuan/article/details/44957589

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!