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问题描述:
Given a 2dgrid map of ‘1‘s (land) and‘0‘s (water),count the number of islands. An island is surrounded by water and is formed byconnecting adjacent lands horizontally or vertically. You may assume all fouredges of the grid are all surrounded by water.
Example 1:
11110
11010
11000
00000
Answer: 1
Example 2:
11000
11000
00100
00011
Answer: 3
Credits:
Special thanks to @mithmatt
for adding this problem andcreating all test cases
问题分析:一个简单的DFS(深度优先遍历)算法,这里避免开辟新空间来标志每个节点是否被访问,修改grid[][]对应的值不为题目设定的’0’或’1’即可;
代码:
public class Solution { public int numIslands(char[][] grid) { if(grid == null || grid.length == 0) return 0; int result = 0; for(int i = 0; i < grid.length; i++) { for(int j = 0; j < grid[0].length; j++) { if(grid[i][j] == '1') { dfs_visit(grid, i, j); result ++; } } } return result; } //访问函数 private void dfs_visit(char[][] grid, int i, int j) { if(i < 0 || i >= grid.length || j < 0 || j >= grid[0].length) return; if(grid[i][j] != '1') return; grid[i][j] = '2';//表示已经访问过该节点 dfs_visit(grid, i + 1, j); dfs_visit(grid, i - 1, j); dfs_visit(grid, i, j + 1); dfs_visit(grid, i, j - 1); return; } }
leetcode-200 Number of Islands
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原文地址:http://blog.csdn.net/woliuyunyicai/article/details/44961885