hdu 4528 小明系列故事——捉迷藏

标签：

一开始很疑惑自己为什么错了，后来才知道原来这题是可以往回 走的.开4维visit数组记录状态，状态不同则往回走，相同再往回走.

1
30 31 95
S..............................
..X............................
...X...........................
....X..........................
.....X.........................
......X........................
.......X.......................
........X......................
.........X.....................
..........X....................
...........X...................
............X..................
.............X.................
..............X................
...............X...............
................X..............
.................X.............
..................X............
...................X...........
....................X..........
.....................X.........
......................X........
.......................X.......
........................X......
.........................X.....
..........................X....
...........................X...
............................X..
.............................XE
..............................D

结果是88，如果这组数据能过那就没问题了.

#include<iostream>
#include<queue>
#include<cstring>
using namespace std;
int n,m,t;
char mapp[105][105];
int visit[105][105][2][2];
int dir[4][2]={{0,1},{0,-1},{1,0},{-1,0}};
int dx,dy,ex,ey,sx,sy;
int re;
int flag1,flag2;
struct stu
{
    int x,y,s;
    int flag1,flag2;
};
int judgee(int x,int y)
{
    int flag=0;
    if(x==ex)
    {
        int nn=min(y,ey),mm=max(y,ey);
        int sum=0;
        for(int i=nn+1;i<mm;i++)
        {
            if(mapp[x][i]=='.') sum++;
        }
        if(sum==(mm-nn-1)) flag=1;
    }
    if(y==ey)
    {
        int nn=min(x,ex),mm=max(x,ex);
        int sum=0;
        for(int i=nn+1;i<mm;i++)
        {
            if(mapp[i][y]=='.') sum++;
        }
        if(sum==(mm-nn-1)) flag=1;
    }
    return flag;
}
int judged(int x,int y)
{
    int flag=0;
    if(x==dx)
    {
        int nn=min(y,dy),mm=max(y,dy);
        int sum=0;
        for(int i=nn+1;i<mm;i++)
        {
            if(mapp[x][i]=='.') sum++;
        }
        if(sum==(mm-nn-1)) flag=1;
    }
    if(y==dy)
    {
        int nn=min(x,dx),mm=max(x,dx);
        int sum=0;
        for(int i=nn+1;i<mm;i++)
        {
            if(mapp[i][y]=='.') sum++;
        }
        if(sum==(mm-nn-1)) flag=1;
    }
    return flag;
}
void bfs()
{
    stu x,y;
    queue<stu>root;
    x.x=sx;x.y=sy;x.s=0;x.flag1=0;x.flag2=0;
    root.push(x);
    if(judgee(x.x,x.y)) x.flag1=1;
    if(judged(x.x,x.y)) x.flag2=1;
    visit[x.x][x.y][x.flag1][x.flag2]=1;
    while(root.size())
    {
        x=root.front();
        //cout<<x.x<<x.y<<endl;
        if(judgee(x.x,x.y)) x.flag1=1;
        if(judged(x.x,x.y)) x.flag2=1;
        //cout<<x.x<<x.y<<x.flag1<<x.flag2<<endl; 
        if(x.flag1&&x.flag2) {re=x.s;return;}
        root.pop();
        for(int i=0;i<4;i++)
        {
            y.x=x.x+dir[i][0];
            y.y=x.y+dir[i][1];
            y.flag1=x.flag1;
            y.flag2=x.flag2;
            y.s=x.s+1;
            if(y.x<0||y.x>=n||y.y<0||y.y>=m||visit[y.x][y.y][y.flag1][y.flag2]||mapp[y.x][y.y]!='.'||y.s>t){continue;}
            root.push(y);
            visit[y.x][y.y][y.flag1][y.flag2]=1;
        }
    } 
}
int main()
{
    int u,p;
    cin>>u;
    for(int p=0;p<u;p++)
    {
        cin>>n>>m>>t;
        for(int i=0;i<n;i++)
        {
            for(int j=0;j<m;j++)
            {
                cin>>mapp[i][j];
                if(mapp[i][j]=='S') sx=i,sy=j;
                if(mapp[i][j]=='E') ex=i,ey=j;
                if(mapp[i][j]=='D') dx=i,dy=j;
               // visit[i][j]=-1;
            }
        }
        memset(visit,0,sizeof(visit));
        mapp[sx][sy]='.';
        re=-1;
        bfs();
        cout<<"Case "<<p+1<<":"<<endl;
        cout<<re<<endl;
    }
    return 0;
}

hdu 4528 小明系列故事——捉迷藏

标签：

原文地址：http://blog.csdn.net/zafkiel_nightmare/article/details/44995363