LeetCode-Pow(x, n)

public double Pow(double x, int n) 
    {
        if(n == 0)
        {
            return 1;
        }
        
        int t = Math.Abs(n / 2);
        
        double result = Pow(x, t);
        
        if(n % 2 == 0)
        {
            result = result * result;
        }
        else
        {
            result = result * result * x;
        }
        
        return n > 0 ? result : 1/result;
    }

public double Pow(double x, int n) 
    {
            if (n == 0)
            {
                return 1;
            }

            double result = 1;

            int t = n != int.MinValue ? Math.Abs(n) : Math.Abs(n + 1);
            if (n == int.MinValue)
            {
                result *= x;
            }

            while (t > 0)
            {
                if (t % 2 == 0)
                {
                    x *= x;
                    t /= 2;
                }
                else
                {
                    result *= x;
                    t--;
                }
            }

            return n > 0 ? result : 1 / result;
    }