Given a Weather
table, write a SQL query to find all dates‘ Ids with higher
temperature compared to its previous (yesterday‘s) dates.
+---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------+------------------+For example, return the following Ids for the above Weather table:
+----+ | Id | +----+ | 2 | | 4 | +----+
select b.id as Id from Weather a, Weather b where to_days(a.date) = to_days(b.date) - 1 and a.temperature < b.temperature
原文地址:http://blog.csdn.net/u012925008/article/details/45008331