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Valid Palindrome

时间:2015-04-12 17:30:50      阅读:99      评论:0      收藏:0      [点我收藏+]

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Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.

 

Analyse: 注意大小写形式是等价的,即:A与a等价

 1 class Solution {
 2 public:
 3     bool isPalindrome(string s) {
 4         if(s.length() == 0) return true;
 5         
 6         for(int i = 0, j = s.length() - 1; i < j; i++, j--){
 7             if(!isalnum(s[i]) && !isalnum(s[j])) continue;
 8             
 9             if(!isalnum(s[i])) j++;
10             else if(!isalnum(s[j])) i--;
11             else{
12                 int compare = abs(s[i] - s[j]);
13                 if(compare && compare != 32) return false;
14             }
15         }
16         return true;
17     }
18 };

 

Valid Palindrome

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原文地址:http://www.cnblogs.com/amazingzoe/p/4419789.html

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