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Flatten Binary Tree to Linked List *

时间:2015-04-12 20:56:55      阅读:122      评论:0      收藏:0      [点我收藏+]

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Given a binary tree, flatten it to a linked list in-place.

For example,
Given

         1
        /        2   5
      / \        3   4   6

 

The flattened tree should look like:

   1
         2
             3
                 4
                     5
                         6

 

先序遍历2叉树并将节点依次存入list中,在用list建树代码如下:

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    
    List<TreeNode> list = new ArrayList<TreeNode>();
    
    public void PreOrderTraverse(TreeNode root) {
        if(root!=null) {
            list.add(root);
            if(root.left!=null) PreOrderTraverse(root.left);
            if(root.right!=null) PreOrderTraverse(root.right);
        }
    }
    
    public void flatten(TreeNode root) {
        PreOrderTraverse(root);
        for(int i=0;i<list.size()-1;i++) {
            list.get(i).left = null;
            list.get(i).right =  list.get(i+1);
        }
    }
}

 

 

Flatten Binary Tree to Linked List *

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原文地址:http://www.cnblogs.com/mrpod2g/p/4420219.html

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