标签:c++ poj 2109
技巧。
#include<iostream> #include<cmath> using namespace std; double n,p; int main(){ while(cin>>n>>p){ cout<<pow(p,1/n)<<endl; } }
POJ 2019 Power of Cryptography
原文地址:http://blog.csdn.net/wangxinxin_/article/details/45030073