标签:leetcode
The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
Id | Name | Salary | ManagerId |
---|---|---|---|
1 | Joe | 70000 | 3 |
2 | Henry | 80000 | 4 |
3 | Sam | 60000 | NULL |
4 | Max | 90000 | NULL |
Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
Employee |
---|
Joe |
题目是要从Employee表中找到员工的工资大于自己manager工资的员工姓名。
实现方案也是MYSQL的内联,直接上AC SQL。
select e1.Name from Employee as e1 inner join Employee as e2
on e1.ManagerId = e2.Id and e1.Salary > e2.Salary;
[LeetCode]Employees Earning More Than Their Managers,解题报告
标签:leetcode
原文地址:http://blog.csdn.net/wzy_1988/article/details/45030839