标签:database leetcode sql postgresql
The Employee
table holds all employees. Every employee has an Id, and there
is also a column for the department Id.
+----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000 | 1 | | 2 | Henry | 80000 | 2 | | 3 | Sam | 60000 | 2 | | 4 | Max | 90000 | 1 | | 5 | Janet | 69000 | 1 | | 6 | Randy | 85000 | 1 | +----+-------+--------+--------------+
The Department
table holds all departments of the company.
+----+----------+ | Id | Name | +----+----------+ | 1 | IT | | 2 | Sales | +----+----------+
Write a SQL query to find employees who earn the top three salaries in each of the department. For the above tables, your SQL query should return the following rows.
+------------+----------+--------+ | Department | Employee | Salary | +------------+----------+--------+ | IT | Max | 90000 | | IT | Randy | 85000 | | IT | Joe | 70000 | | Sales | Henry | 80000 | | Sales | Sam | 60000 | +------------+----------+--------+
select d1.name as department, e1.name as employee, e1.salary as salary from Department d1, Employee e1 where ( select count(distinct e2.salary) from Employee e2 where e2.salary > e1.salary and e2.departmentid = e1.departmentid ) < 3 and d1.id = e1.departmentid;
LeetCode Department Top Three Salaries
标签:database leetcode sql postgresql
原文地址:http://blog.csdn.net/u012925008/article/details/45030895