返回人民币大写方式（num2rmb）

CREATE OR REPLACE FUNCTION num2rmb(Pi_MONEY NVARCHAR2) RETURN NVARCHAR2 IS
  -- PURPOSE :返回人民币大写方式
  v_NUM   NUMBER;
  I       NUMBER;
  J       NUMBER;
  K       NUMBER;
  L       NUMBER;
  FS1     NVARCHAR2(500);
  FS2     NVARCHAR2(500);
  FS3     NVARCHAR2(500);
  S       NVARCHAR2(500);
  S1      NVARCHAR2(500);
  S2      NVARCHAR2(500);
  ZERO    NUMBER;
  POS     NUMBER;
  H       NUMBER;
  T       NUMBER(5, 4);
  v_money NUMBER;
BEGIN
  v_money := round(Pi_MONEY, 2);
  IF NVL(v_money, 0) = 0
     OR INSTR(v_money, ‘.‘) >= 18 THEN
    RETURN ‘无‘;
  END IF;
  ZERO := 0;
  POS  := 0;
  FS1  := ‘零壹贰叁肆伍陆柒捌玖‘;
  FS2  := ‘仟佰拾万仟佰拾元‘;
  FS3  := ‘仟佰拾万仟佰拾亿‘;
  H    := TRUNC(v_money); ---整数部分
  T    := v_money - H; ---小数部分
  IF T = 0 THEN
    ---形成字符串
    S := LPAD(TO_CHAR(H), 16, ‘0‘) || ‘.0000‘;
  ELSE
    S := LPAD(TO_CHAR(H), 16, ‘0‘) || RPAD(TO_CHAR(T), 5, ‘0‘);
  END IF;
  S1 := SUBSTR(S, 1, 8) || ‘.‘;
  --整理亿位数字
  FOR I IN 1 .. 8 LOOP
    IF I >= POS THEN
      --- else skip 0
      L := TO_NUMBER(SUBSTR(S1, I, 1));
      IF L > 0 THEN
        --add fs1 and fs2 char
        S2   := S2 || SUBSTR(FS1, L + 1, 1) || SUBSTR(FS3, I, 1);
        ZERO := 1; --有整数
      ELSE
        IF I = 4 THEN
          S2 := S2 || ‘万‘;
        END IF; ---插入万字，因为从此出分隔一次循环
        POS := I + 1;
        FOR J IN I + 1 .. 9 LOOP
          IF J = 4
             AND SUBSTR(S1, J, 1) = ‘0‘
             AND S2 IS NOT NULL
             AND ZERO = 1 THEN
            S2 := S2 || ‘万‘;
          END IF;
          IF SUBSTR(S1, J, 1) = ‘0‘ THEN
            POS := POS + 1;
          END IF;
          EXIT WHEN SUBSTR(S1, J, 1) != ‘0‘; --POS >= 9;
        END LOOP;
        IF POS = 9
           AND SUBSTR(S1, 1, 8) >= 1 THEN
          S2 := S2 || ‘亿‘; --无个亿位,直接加亿
        ELSE
          IF ZERO = 1 THEN
            S2 := S2 || ‘零‘;
          END IF; --不到个亿位,补中间零 eg 10101
        END IF;
      END IF;
    END IF;
  END LOOP;
  ZERO := 0;
  POS  := 0;
  --整理亿位之后的数据
  S1 := SUBSTR(S, 9);
  FOR I IN 1 .. 8 LOOP
    IF I = 1
       AND TO_NUMBER(SUBSTR(S1, I, 1)) = 0
       AND S2 IS NOT NULL THEN
      S2 := S2 || ‘零‘;
    END IF;
    IF I >= POS THEN
      --- else skip 0
      L := TO_NUMBER(SUBSTR(S1, I, 1));
      IF L > 0 THEN
        --add fs1 and fs2 char
        S2   := S2 || SUBSTR(FS1, L + 1, 1) || SUBSTR(FS2, I, 1);
        ZERO := 1; --有整数
      ELSE
        IF I = 4 THEN
          S2 := S2 || ‘万‘;
        END IF; ---插入万字，因为从此出分隔一次循环
        POS := I + 1;
        FOR J IN I + 1 .. 9 LOOP
          IF J = 4
             AND SUBSTR(S1, J, 1) = ‘0‘
             AND S2 IS NOT NULL
             AND ZERO = 1 THEN
            S2 := S2 || ‘万‘;
          END IF;
          IF SUBSTR(S1, J, 1) = ‘0‘ THEN
            POS := POS + 1;
          END IF;
          EXIT WHEN SUBSTR(S1, J, 1) != ‘0‘;
        END LOOP;
        IF POS = 9
           AND v_money >= 1 THEN
          S2 := S2 || ‘元‘; --无个位,直接加元
        ELSE
          IF ZERO = 1 THEN
            S2 := S2 || ‘零‘;
          END IF; --不到个位,补中间零 eg 10101.00
        END IF;
      
      END IF;
    END IF;
  END LOOP;
  IF SUBSTR(S1, 10, 4) = ‘0000‘ THEN
    S2 := S2 || ‘整‘;
  ELSE
    L := TO_NUMBER(SUBSTR(S1, 10, 1));
    IF L > 0 THEN
      S2 := S2 || SUBSTR(FS1, L * 1 + 1, 1) || ‘角‘;
    ELSE
      IF v_money > 0.1 THEN
        S2 := S2 || ‘零‘;
      END IF; --去掉0.01的前导零
    END IF;
    L := TO_NUMBER(SUBSTR(S1, 11, 1));
    IF L > 0 THEN
      S2 := S2 || SUBSTR(FS1, L * 1 + 1, 1) || ‘分‘;
    END IF;
  END IF;
  RETURN S2;
END num2rmb;